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zaharov [31]
2 years ago
9

Helpppp how do I do this? ​

Mathematics
1 answer:
zhannawk [14.2K]2 years ago
5 0

The angles shown are

  • <QPR
  • <SPR

PR is the bisector of angle P

So

  • <P=<QPR+<SPR or =<QPS
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At the beginning of an experiment, the number of bacteria in a colony was counted at time t=O. The number of bacteria in the col
yan [13]

Answer:

1092

Step-by-step explanation:

We have been given that the number of bacteria in the colony t minutes after the initial count modeled by the function B(t)=9(3)^t. We are asked to find the average rate of change in the number of bacteria over the first 6 minutes of the experiment.

We will use average rate of change formula to solve our given problem.

\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}

Upon substituting our given values, we will get:

\text{Average rate of change}=\frac{b(6)-b(0)}{6-0}

\text{Average rate of change}=\frac{9(3)^6-9(3)^0}{6}

\text{Average rate of change}=\frac{9(729)-9(1)}{6}

\text{Average rate of change}=\frac{6561-9}{6}

\text{Average rate of change}=\frac{6552}{6}

\text{Average rate of change}=1092

Therefore, the average rate of change in the number of bacteria is 1092 bacteria per minute.

8 0
3 years ago
Please help. Use PEMDAS
german
This order,

P: Parentheses

E: Exponents

M: Multiplication

D: Division

A: Addition

S: Subtraction
4 0
3 years ago
Read 2 more answers
A(x+b)=c solve for x
ValentinkaMS [17]
A(x + b) = c
x+b = c / A
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Hope this helps!

4 0
3 years ago
(-4q^2-22q+12)/(2q+1) Please show working Need help ASAP! I will be very grateful for help!
jasenka [17]
First factor (-4q^2-22q+12), and you end up with −2(q+6)(2q−1)now rewrite your expression as: −2(q+6)(2q−1)/(2q+1)
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3 0
4 years ago
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I NEED HELP PLEASE! ASAP PLEASE!<br><br> Solve the problem.<br><br> m + 7 &gt; 13<br><br> m &gt;
a_sh-v [17]

Answer:

<em>m</em> > 6

Step-by-step explanation:

Move all terms not containing <em>m </em>to the right side of the inequality.

Inequality Form:

<em>m </em>> 6

Interval Notation:

(6, ∞)

Therefor, the answer would be:

<em>m </em>> 6

Hope this helps!

4 0
3 years ago
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