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2 years ago

Helpppp how do I do this?

Mathematics

1 answer:

zhannawk [14.2K]2 years ago

5 0

The angles shown are

<QPR
<SPR

PR is the bisector of angle P

<P=<QPR+<SPR or =<QPS

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Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5

lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer: v = 5v + 4u + 1.5sin(3t),

1.5sin(3t)

Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t) where u'(1) = 2.5 u(1) = 1

v represents the "velocity function" i.e v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v' = 5u' + 4u + 1.5sin(3t) ( given that u" - 5u' - 4u = 1.5sin(3t) )

= 5v + 4u + 1.5sin(3t) ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt $\left[\begin{array}{ccc}u&\\v&\\\end{array}\right]$ = $\left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]$ $\left[\begin{array}{ccc}u&\\v&\\\end{array}\right]$ + $\left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]$

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

$\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]$ = $\left[\begin{array}{ccc}1\\2.5\\\end{array}\right]$

7 0

3 years ago

Help me with all these questions plz!!!

garri49 [273]

First: 10
Second: 10
Third: 10
They are all 10 times smaller than the other one.
Hope this helped. :D

3 0

3 years ago

Read 2 more answers

What is the Value of x+y ? PLZ Help ASAP

Natalija [7]

ANSWER

$x + y = 60$

EXPLANATION

Method 1

Vertically opposite angles are equal, therefore

$3x + 55 = 85$

This implies that,

$3x = 85 - 55$

We simplify to get,

$3x = 30$

Dividing through by 3 gives,

$x = 10$

Also,

$2y - 5 = 95$

This implies that,

$2x = 95 + 5$

We simplify the right hand side to get,

$2x = 100$

We divide both sides both sides by 2 to get,

$x = 50$

$x + y = 50 + 10$

$x + y = 60$

Method 2

Angles on straight line sums to 180°.

$2y-5+85=180$

This implies that,

$2y+80=180$

$2y=180-80$

$2y=100$

$y=50$

Also,

$3x+55+95=180$

$3x+150=180$

$3x=180-150$

$3x=30$

$x=10$

$x+y=50+10$

$x+y=60$