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IceJOKER [234]
3 years ago
13

Simplify 2x(-11x - 7)

Mathematics
2 answers:
LekaFEV [45]3 years ago
7 0
The answer will be -22x^2-14x. Hope it help!
zhannawk [14.2K]3 years ago
4 0
The answer is -22x²-14x. You get this answer by using the distributive property.
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Use the Law of Cosines to find the specified missing value. Approximate your answer to the nearest tenth.
Charra [1.4K]
<h3>Answer:  176.6</h3>

Work Shown:

b^2 = a^2 + c^2 - 2*a*c*\cos(B)\\\\b^2 = 150^2 + 30^2 - 2*150*30*\cos(150)\\\\b^2 \approx 31194.22863406\\\\b \approx \sqrt{31194.22863406}\\\\b \approx 176.618879608211\\\\b \approx 176.6\\\\

4 0
2 years ago
Find the missing side length to the nearest tenth of a millimeter.
wel

Answer:

17.9

Step-by-step explanation:

3.7²+17.5²=319.94

\sqrt{319.94\\= 17.9

8 0
3 years ago
If f(x)= -2x²-,find f(0).​
IRINA_888 [86]

Answer:

0

Step-by-step explanation:

f(0) = -2(0)²

= -2(0)

= 0

6 0
3 years ago
PLEASE HELP FAST!<br><br><br> what is the length of segment AB? <br> 10<br> 12<br> 13<br> 15
ss7ja [257]

Answer:

13

Step-by-step explanation:

This triangle appears to be 5 units wide and 12 units tall.

Using the pythagorean theorem, a^2 + b^2 = c^2, we get 25 + 144 = 169 or 13^2.

Therefore the answer is 13.

4 0
3 years ago
Read 2 more answers
A 5-gallon jug of cleaning solution contains 6% bleach. How much pure water should be added to it to dilute to 4% bleach?
mihalych1998 [28]
Let's bear in mind that 5 gallons with a solution of 6% bleach, contains some water plus some bleach, how much bleach?  well, is just 6% of 5 gallons or namely (6/100) * 5 gallons, or 0.30 gallons.

if we use "x" gallons of water, well pure water has no bleach, so is 0% bleach, and it has a (0/100) * x or 0x gallons of bleach.

the mixture will be say "y" gallons, and is 4% bleach, so (4/100) * y is 0.04y gallons in the mixture of bleach.

\bf \begin{array}{lcccl}&#10;&\stackrel{gallons}{quantity}&\stackrel{\textit{\% of bleach}}{amount}&\stackrel{\textit{gallons of bleach}}{amount}\\&#10;&------&------&------\\&#10;\textit{pure water}&x&0.00&0x\\&#10;\textit{6\% solution}&5&0.06&0.3\\&#10;-----&------&------&------\\&#10;mixture&y&0.04&0.04y&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;x+5=\boxed{y}\\&#10;0x+0.3=0.04y\\&#10;---------\\&#10;0.3=0.04\left( \boxed{x+5} \right)&#10;\end{cases}&#10;\\\\\\&#10;0.3=0.04x+0.2\implies 0.1=0.04x\implies \cfrac{0.1}{0.04}=x\implies 2.5=x
3 0
3 years ago
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