Square has 4 equal sides so it would be the same for all the corresponding sides.
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area of triangle =
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PLEASE HELP QUICKLY!!!
2 answers:
Answer:
The Regression line is that line , which passes through all the points , through a single point , or none of the points.
Here, the table is about ,weight of a dog in pounds at various ages in months.
The ratio of Weight at different stages,of months should be proportional.
So, if you look at option (1) , the ratio of x to y in three cases are same that is
It means Regression line is Passing through three points, means Dog's weight at three different stages of month are same.and in other tables the ratio are not equivalent.
So, Table 1, that is option 1
is true.
x: 3, 4, 6, 8, 9, 12
y: 2, 5, 7, 10, 11, 15
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I: x-2y>=8
II:2x+y<=3
start by isolating y on a side
with I:
x-2y>=8
-2y>=8-x
2y<=x-8
y<=x/2-4
with II:
2x+y<=3
y<=-2x+3
now you can draw I' and II' and read of the solutions with the graph.
transform the inequalities into lines in slope intercept form by replacing the inequality with equality:
y<=x/2-4
->
y=x/2-4
y<=-2x+3
->
y=-2x+3
look at the inequalities to figure out if the area above or below is valid for each line (y<=... -> area below is valid->colored in the attached image)
the area in which all areas overlap is the solution space.
II:2x+y<=3
start by isolating y on a side
with I:
x-2y>=8
-2y>=8-x
2y<=x-8
y<=x/2-4
with II:
2x+y<=3
y<=-2x+3
now you can draw I' and II' and read of the solutions with the graph.
transform the inequalities into lines in slope intercept form by replacing the inequality with equality:
y<=x/2-4
->
y=x/2-4
y<=-2x+3
->
y=-2x+3
look at the inequalities to figure out if the area above or below is valid for each line (y<=... -> area below is valid->colored in the attached image)
the area in which all areas overlap is the solution space.