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3 years ago

(2x+5)/3=-7 show all work

Mathematics

1 answer:

Phantasy [73]3 years ago

3 0

→(2X+5)=-21→2X=-26→X=-13

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Show that √(1-cos A/1+cos A) =cosec A - cot A

Gennadij [26K]

Hi there!

$\sqrt{\frac{1-cosA}{1+cosA}} =$

We can begin by multiplying by its conjugate:

$\sqrt{\frac{1-cosA}{1+cosA}} * \sqrt{\frac{1+cosA}{1+cosA}} = \\\\\sqrt{\frac{(1-cosA)(1 + cosA)}{(1+cosA)(1 + cosA)}} =$

Simplify using the identity:

$1 - cos^2A = sin^2A$

$\sqrt{\frac{(1-cos^2A)}{(1+cosA)^2}} =\\\\\sqrt{\frac{(sin^2A)}{(1+cosA)^2}} =$

Take the square root of the expression:

${\frac{sinA}{1+cosA} =$

Multiply again by the conjugate to get a SINGLE term in the denominator:

${\frac{sinA}{1+cosA} * {\frac{1-cosA}{1-cosA} =\\$

Simplify:

${\frac{sinA(1-cosA)}{1-cos^2A} =$

Use the above trig identity one more:

${\frac{sinA(1-cosA)}{sin^2A} =$

Cancel out sinA:

${\frac{(1-cosA)}{sinA} =$

Split the fraction into two:

${\frac{1}{sinA} - \frac{cosA}{sinA} =$

Recall:

$1/sinA = cscA\\\\cosA/sinA = cotA$

Simplify:

$\frac{1}{sinA} + \frac{cosA}{sinA} = \boxed{cscA - cotA}$

5 0

2 years ago

Can someone help me with this asap.

Sever21 [200]

Answer:

fourth option

Step-by-step explanation:

Given

3x < - 9 ( divide both sides by 3 )

x < - 3

solution set is { x | x < - 3 }

4 0

2 years ago

-1/4x -8<3/4 X<9 X>-35 X<8 3/4 X <2 3/16

hodyreva [135]

Answer:

Ans is behind it

Step-by-step explanation:

hope it helps uh

8 0

3 years ago

What property is 3(x+2)=2x-10

Mandarinka [93]

The answer is x= -16

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3 years ago

Which system of equations has the same solution as the system below??! PLEASE HELP

Fantom [35]

The answer is the second one, 2.

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3 years ago