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Mariulka [41]
2 years ago
7

HELP! abcdefghijklmnopqrstuvwxyz

Mathematics
2 answers:
Darya [45]2 years ago
5 0

Answer:

5

5*3 =15

15*3=45

45*3 =135

------------------------

Step-by-step explanation:

WITCHER [35]2 years ago
3 0
the answer is most likely 135
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James invests $5,000 at an annual rate of 8% simple interest for 7 years. How much is in the account
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$8,569.12

Step-by-step explanation:

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3 years ago
Please help me out with these no one is helping me.<br>Please anyone <br>​
Olin [163]

Answer:

Below.

Step-by-step explanation:

You find the values of y by substituting the values of x in the expression x^2 + 3x - 1.

So f(-4) = (-4)^2 + 3(-4) - 1 = 16-12-1 = 3

in the same way  f(-3) = -1, f(-2) = -3, f(-1) = -3,

f(0) = -1 and f(1) = 3.

Now plot the points (-4, 3) , (-3, -1) and so on  

Then you can read the values off this graph.

8 0
3 years ago
Read 2 more answers
Factor the equation 8y-36
musickatia [10]
4(2y−9) is the correct answer
6 0
3 years ago
The circumference of a circle is 16Pi ft.<br><br> The radius is <br> ft.
mafiozo [28]
8pi ft

Just divide 16 by 2 because it’s half of the diameter
6 0
3 years ago
(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

3 0
3 years ago
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