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Crank
3 years ago
15

Can anyone please help me?!?!?!?!?!?

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
8 0
Im pretty sure its 12x

Leya [2.2K]3 years ago
7 0
2) 3x+4x+5x= 12x

if you need help on others ask :)
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What number is 0.01 less than 24?<br><br> Please help!
balandron [24]

Answer:

23.99

Step-by-step explanation:

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Hector wants to run 18 hours by first track meet .suppose he runs the same number of hours and week 2 and week 3 of his training
ratelena [41]
Answer : do 18x3 and that's your answer
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3 years ago
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The amounts (in ounces) of randomly selected eight 16-ounce beverage cans are given below. See Attached Excel for Data. Assume t
motikmotik

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The amounts (in ounces) of randomly selected eight 16-ounce beverage cans are given below.

16.5, 15.2, 15.4, 15.1, 15.3, 15.4, 16, 15.1

Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans and fill in the blanks appropriately.

A 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is ( , ) ounces. (round to 3 decimal places)

Answer:

99\% \: \text {confidence interval} = (14.886, \: 16.113)\\\\

Therefore, the 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (14.886, 16.113) ounces.

Step-by-step explanation:

Let us find out the mean amount of the 16-ounce beverage cans from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

\bar{x} = 15.5

Let us find out the standard deviation of the 16-ounce beverage cans from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

$ s = 0.4957 $

The confidence interval is given by

\text {confidence interval} = \bar{x} \pm MoE\\\\

Where \bar{x} is the sample mean and Margin of error is given by

$ MoE = t_{\alpha/2} \cdot (\frac{s}{\sqrt{n} } ) $ \\\\

Where n is the sample size, s is the sample standard deviation and  is the t-score corresponding to a 99% confidence level.

The t-score corresponding to a 99% confidence level is

Significance level = α = 1 - 0.99 = 0.01/2 = 0.005

Degree of freedom = n - 1 = 8 - 1 = 7

From the t-table at α = 0.005 and DoF = 7

t-score = 3.4994

MoE = t_{\alpha/2}\cdot (\frac{s}{\sqrt{n} } ) \\\\MoE = 3.4994 \cdot \frac{0.4957}{\sqrt{8} } \\\\MoE = 3.4994\cdot 0.1753\\\\MoE = 0.6134\\\\

So the required 99% confidence interval is

\text {confidence interval} = \bar{x} \pm MoE\\\\\text {confidence interval} = 15.5 \pm 0.6134\\\\\text {confidence interval} = 15.5 - 0.6134, \: 15.5 + 0.6134\\\\\text {confidence interval} = (14.886, \: 16.113)\\\\

Therefore, the 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (14.886, 16.113) ounces.

8 0
4 years ago
Isabel’s team won their baseball game and scored 60 points total . If Isabel scored 12 of the points and everyone else scored 8
Studentka2010 [4]

Answer:

6 people on her team

Step-by-step explanation:

60-12= 48

48/8= 6

6 0
4 years ago
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3HELP__________________
Brut [27]

Answer:

m∠KIJ = m∠LIM ⇒ answer B

Step-by-step explanation:

* Lets explain how to solve the problem

∵ I is the mid-point of NH

∴ IN = IH

- MJ is perpendicular to NH and passes through I the mid-point of NH

∴ MJ is perpendicular bisector of NH

- NH ⊥ MJ and intersects it at I

∴ m∠NIM = m∠NIJ = 90°

- ∠ NIM consists of two angles ∠NIL and ∠MIL

∵ m∠NIM = m∠NIL + m∠MIL

- ∠NIJ consists of two angles ∠NIK and ∠JIK

∵ m∠NIJ = m∠NIK + m∠JIK

∴ m∠NIL + m∠MIL = m∠NIK + m∠JIK ⇒ (1)

∵ NH bisects ∠KIL

∴ m∠NIL = m∠NIK ⇒ (2)

- From (1) and (2)

∴ m∠MIL = m∠JIK

* m∠KIJ = m∠LIM

7 0
3 years ago
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