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3 years ago

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Mathematics

1 answer:

Brut [27]3 years ago

7 0

Answer:

m∠KIJ = m∠LIM ⇒ answer B

Step-by-step explanation:

* Lets explain how to solve the problem

∵ I is the mid-point of NH

∴ IN = IH

- MJ is perpendicular to NH and passes through I the mid-point of NH

∴ MJ is perpendicular bisector of NH

- NH ⊥ MJ and intersects it at I

∴ m∠NIM = m∠NIJ = 90°

- ∠ NIM consists of two angles ∠NIL and ∠MIL

∵ m∠NIM = m∠NIL + m∠MIL

- ∠NIJ consists of two angles ∠NIK and ∠JIK

∵ m∠NIJ = m∠NIK + m∠JIK

∴ m∠NIL + m∠MIL = m∠NIK + m∠JIK ⇒ (1)

∵ NH bisects ∠KIL

∴ m∠NIL = m∠NIK ⇒ (2)

- From (1) and (2)

∴ m∠MIL = m∠JIK

* m∠KIJ = m∠LIM

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Which expressions are equivalent to ln x 2 ln 5 ln 1? Check all that apply. 2 ln 5x ln (x 26) ln 25x ln 1 ln 25x.

Marysya12 [62]

Equivalent expression is the expression of two equation when the way of representation of the two equation is different but the result is same.The expressions which are equivalent to the given expression are,

$\ln25+\ln1$
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Given information-

The expression given in the problem is,

$\ln x+2 \ln 5 +\ln1$

<h3>Equivalent expression-</h3>

Equivalent expression is the expression of two equation when the way of representation of the two equation is different but the result is same.

For given expression,

$\ln x+2 \ln 5 +\ln1$

As the above function is the function of <em>x. </em>Thus it can be written as,

$f(x)=\ln x+2 \ln 5 +\ln1$

<h3>Logarithm power rule</h3>

Logarithm power rule states that the exponent of the logarithm function can transfers to front of the logarithm and vice versa. Thus,

$f(x)=\ln x+ \ln 5^2 +\ln1\\
f(x)=\ln x+ \ln 25 +\ln1$

Now the value of $\ln 1$ is equal to the zero. Thus,

$f(x)=0+\ln 25 +\ln1\\
f(x)=0+\ln 25 +\ln1\\
f(x)=\ln 25 +\ln1\\
f(x)=\ln 25 +0\\
f(x)=\ln 25$

Hence the expressions which are equivalent to the given expression are,

$\ln25+\ln1$
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2 years ago

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Let's make green = g(x) and pink = p(x)
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3 years ago

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Sergio [31]

Answer:

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Step-by-step explanation:

Let the number be x and y

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