3 years ago

What is the sum? 3k/k^2+k-7/4K

1 answer:

3 0

Answer:

$\dfrac{k^2+5k}{4k^2}$

Step-by-step explanation:

A suitable common denominator is 4k^2. (This eliminates the first and last choices.)

$\dfrac{3k}{k^2}+\dfrac{k-7}{4k}=\dfrac{4(3k)}{4(k^2)}+\dfrac{k(k-7)}{k(4k)}\\\\=\dfrac{12k+k^2-7k}{4k^2}=\boxed{\dfrac{k^2+5k}{4k^2}}$

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