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musickatia [10]
3 years ago
12

What is the value of five in 3156

Mathematics
2 answers:
slava [35]3 years ago
8 0

Answer:

Hey there!

The five is located in the tens place, so the value would be 5(10), or 50.

Let me know if this helps :)

arlik [135]3 years ago
5 0
In the 10th place



explaintion is
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Help please. will give brainliest. i think it is b or c.
vagabundo [1.1K]

Answer:

Third option, letter c

Explanation:

3/8 are male, so the chance for 1 year is 3/8

Then for 2 years in a row, the chance decreases, so it is: 3/8.3/8=9/64 or (3/8)^2

Hope you get it!

8 0
3 years ago
Ali bought 20 dozen oranges 10% of them were rotten. How many oranges were good ?​
Mashutka [201]

Answer:

Step-by-step explanation:

rotten oranges=10/100*20

200/100

2 dozen

good oranges=total dozen-rotten oranges

20-2

18 d0zen were good oranges.

5 0
2 years ago
Solve for x: 4 − (x + 2) −7<br> x −9
olga2289 [7]

Answer:

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8 0
3 years ago
Read 2 more answers
A waitress works 1.75 hours less in the afternoon than in the evening. If she works 5      1/8
gayaneshka [121]
Let x be the number of hours that the waitress works in the evening.

We know for our problem that she works 5 \frac{1}{8} in the afternoon and that she works <span>1.75 hours less in the afternoon than in the evening, so:
</span>x=5 \frac{1}{8} -1.75
<span>Since </span>\frac{1}{8} =0.125, we can rewrite our expression:
x=5.125-1.75
x=3.375

We can conclude that she works 3.375 hours in the evening, or expressed as a mixed fraction: 3 \frac{3}{8} hours.
3 0
3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
11111nata11111 [884]

Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

5 0
3 years ago
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