189 : 3 = 63
63 : 3 = 21
21 : 3 = 7
7 : 7 = 1
<h3>189 = 3 · 3 · 3 · 7 = 3³ · 7</h3>
Answer:
n^2 + 3.
Step-by-step explanation:
4 7 12 19
Differences are 3 5 7 so this a quadratic sequence.
2nd difference = 2 2
So the first part of the expression is n^2
Terms: 4 7 12 19
n^2 1 4 9 16
Difference = 3 3 3 3 3
So the answer is n^2 + 3.
To eliminate x, the coefficients of x's in both equations should be opposite numbers. Since the coefficient of x in the second equation is 3, the coefficient in the first equation should be -3. So she should multiply the first equation by -3.
Hello :
let : x this number
10√x = 40 x ..... x <span>> 0
</span>√x = 4 x and : x > 0
(√x )²= (4 x)² and : x > 0
x = 16 x² ....x > 0 : i'can simplifiy by : x
1 =16x
x = 1/16
Answer:
Step-by-step explanation:
the prime factors of 1470= 2 x 3 x 5 x 7 x 7
also of 7056=2 x 2 x 2 x 2 x 3 x 3 x 7 x 7
hence of
1470 x 7056=2 x 3 x 5 x 7 x 7 x 2 x 2 x 2 x 2 x 3 x 3 x 7 x 7
required answer pls hit the stars and brain-list it
