Question

Plz help Show work Thank youuuuuuuu

Answer 1

For this case we have:

Diana:

$\frac {3} {8}$ mile in 5 minutes.

To find the speed we divide the distance by the time:

$v = \frac {\frac {3} {8}} {5} = \frac {3} {40} = 0.075 \frac {mile} {min}$

Thus, Diana's speed is $0.075 \frac {mile} {min}$

Fernando:

$2 \frac {1} {2} = \frac {5} {2}$mile in $\frac {3} {4}$

$v = \frac {\frac {5} {2}} {\frac {3} {4}} = \frac {4 * 5} {2 * 3} = \frac {20} {6} = 3.33 \frac {mile} {min}$

Thus, Fernando's speed is$3.33 \frac {mile} {min}$

We find the speed in miles per hour considering that an hour has 60 minutes.

Diana:

$0.075 \frac {mile} {min} * \frac {60} {1} \frac {min} {h} = 4.5 \frac {mile} {h}$

Fernando:

$3.33 \frac {mile} {min} * \frac {60} {1} \frac {min} {h} = 199.8 \frac {mile} {h}$

Answer:

Diana's speed is $0.075 \frac {mile} {min} = 4.5 \frac {mile} {h}$

Fernando's speed is $3.33 \frac {mile} {min} = 199.8 \frac {mile} {h}$