$Use\ (a+b)^2=a^2+2ab+b^2\qquad(*)\\\\y=x^2+6x+10=x^2+2(x)(3)+10=\underbrace{x^2+2(x)(3)+3^2}_{(*)}-3^2+10\\\\=(x+3)^2-9+10=(x+3)^2+1\\\\Answer:\ \boxed{y=(x+3)^2+1}$

3 0

3 years ago

A horse farm is developing a new indoor arena in a rectangular buliding. They want the width of the building to be 3 wide feet a

erastovalidia [21]

Answer:

The area of the building in terms of y in its simplest form is 12(y + 2)

Step-by-step explanation:

Since the area of a rectangle is A = LW where L = length and W = width. From our question, the width of the rectangular building is 3 feet. So, W = 3 feet and its length is 4y + 8 feet. So, L = 4y + 8 feet.

So, the area of the building in terms of y is A = LW

= (4y + 8) × 3

Factorizing out 4 from the expression, we have

= 4(y + 2) × 3

= 12(y + 2)

So, the area of the building in terms of y in its simplest form is 12(y + 2)

8 0

3 years ago