3 is 95 and 4 is 85. I believe
6x-8=8x-10 then 2=2x which means x=1
Answer:
Solution given:
opposite:9
adjacent: 12
![\theta=?](https://tex.z-dn.net/?f=%5Ctheta%3D%3F)
Relationship between opposite and adjacent is given by tan angle
so
![Tan \theta=\frac{opposite} {adjacent}=\frac{9}{12}](https://tex.z-dn.net/?f=Tan%20%5Ctheta%3D%5Cfrac%7Bopposite%7D%20%7Badjacent%7D%3D%5Cfrac%7B9%7D%7B12%7D)
![Tan \theta=\frac{3}{4}](https://tex.z-dn.net/?f=Tan%20%5Ctheta%3D%5Cfrac%7B3%7D%7B4%7D)
![\theta=Tan^{-1}\frac{3}{4}](https://tex.z-dn.net/?f=%5Ctheta%3DTan%5E%7B-1%7D%5Cfrac%7B3%7D%7B4%7D)
![\bold{\theta=36.8°}](https://tex.z-dn.net/?f=%5Cbold%7B%5Ctheta%3D36.8%C2%B0%7D)
#11.
hypotenuse[h]=11cm
opposite/perpendicular[P]=b cm
adjacent/base[b]=a cm
now
![\theta=62°](https://tex.z-dn.net/?f=%5Ctheta%3D62%C2%B0)
Relationship between height and hypotenuse is given by Sin angle
:.
Sin 62°=![\frac{opposite}{hypotenuse}=\frac{b}{11}](https://tex.z-dn.net/?f=%5Cfrac%7Bopposite%7D%7Bhypotenuse%7D%3D%5Cfrac%7Bb%7D%7B11%7D)
doing crisscrossed multiplication
b=Sin 62°*11
:.b=9.71 cm
a) At <u>9</u><u>.</u><u>7</u><u>1</u><u> </u>cm height does the ladder touch the building.
again
Relationship between base and hypotenuse is given by Cos angle
:.Cos 62°=![\frac{base}{hypotenuse}=\frac{a}{11}](https://tex.z-dn.net/?f=%5Cfrac%7Bbase%7D%7Bhypotenuse%7D%3D%5Cfrac%7Ba%7D%7B11%7D)
doing crisscrossed multiplication
a=Cos 62°×11
a=5.16cm
b) the distance between the foot of the ladder and the building is <u>5.16cm.</u>
Answer:
I think it would be group B due to the fact that they are the closest to 25 g
Step-by-step explanation: