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4 years ago

Is 2/3 greater than 2/5?

1 answer:

7 0

Yes. 2/3 is greater than 2/5. You can check this by cross multiplication or easier just look at the denominator and numerator. In this case the numerator is the same so it's easier in a sense that you need to look at the denominator. Since the denominator 3 is close to the numerator 2 it shows that it's almost a whole unlike the other fraction. You can also convert each fraction to decimals and compare it which is also easy. Just divide the numerator by the denominator and you've got a decimal. Hope this helps!

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-3x + 7y = -1 - 2x + 5y=0

Talja [164]

(X,Y) = (9/13 , 2/13)

6 0

3 years ago

THERE ARE 120 CHOCOLATES AND SOME BOXES. EACH BOX HOLDS 9 CHOCOLATES. WHAT IS THE LEAST AMOUNT OF BOXES THAT WILL BE NEEDED ?

mojhsa [17]

Answer: 13

Step-by-step explanation:

first divide and then it comes out 13 then check your math so then it puts 120 its correct

8 0

3 years ago

Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if n = 100.

(2) A Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable X following a Binomial distribution with parameters n and p.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if n = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

8 0

3 years ago

It takes 2 workers 6 days to paint a mansion. How many days would it take 4

marishachu [46]

Answer:

2 workers = 6 days

4 workers = 3 days

Step-by-step explanation:

If it takes 2 workers 6 days, if you seep up the process with 4 workers, you would divide the days by 2 because you multilpied the workers by 2. So, it would take 3 days with 4 workers. I hope that makes sence.

4 0

3 years ago

Si el ∡P y el ∡Q son ángulos alternos internos, y la medida de un ángulo suplementario a uno de ellos mide 135° ,¿cuánto miden e

Hunter-Best [27]

Answer:

so sorry

Step-by-step explanation:

wish I could help but I don't know how to do it

7 0

3 years ago