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lakkis [162]
4 years ago
7

Is 2/3 greater than 2/5?

Mathematics
1 answer:
svetoff [14.1K]4 years ago
7 0
Yes. 2/3 is greater than 2/5. You can check this by cross multiplication or easier just look at the denominator and numerator. In this case the numerator is the same so it's easier in a sense that you need to look at the denominator. Since the denominator 3 is close to the numerator 2 it shows that it's almost a whole unlike the other fraction. You can also convert each fraction to decimals and compare it which is also easy. Just divide the numerator by the denominator and you've got a decimal. Hope this helps!
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In a certain city , the hourly wage of workers on temporary employment crontracts is normally distributed. The mean is $15 and t
Doss [256]

Answer:

16%

Step-by-step explanation:

The mean is $15 and the standar deviation is $3.

mean = 15  and SD = 3

We need to find percentage less than 12 per hour

P(x<12)= P(x=12)

to find P(x=12) we find z-score

z= \frac{x-mean}{SD} =\frac{12-15}{3} =-1

Now use z-score table . z-score = 0.1587

P(x=12)=0.1587

To get percentage we multiply by 100

0.1587 * 100 = 15.87 = 16%

4 0
3 years ago
A man earns 112$ interest in one year on an investment of $1400 what is the rate of his interest
pentagon [3]
$112 / $1400 investment = .08 or 8 Percent interest rate.
8 0
3 years ago
Solve the equation for all real values of x.<br> cosxtanx - 2 cos x=-1
IceJOKER [234]

Solution to equationcosxtanx - 2 cos^2 x=-1 for all real values of x is  x=2k\pi + \frac{\pi}{6}  , x=2k\pi + \frac{5\pi}{6} .

<u>Step-by-step explanation:</u>

Here we have , cosxtanx - 2 cos^2 x=-1. Let's solve :

⇒  cosxtanx - 2 cos^2 x=-1

⇒  cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1

⇒  sinx = 2 cos^2 x-1

⇒  sinx = 2 (1-sin^2x)-1

⇒  sinx = 1-2sin^2x

⇒  2sin^2x+sinx-1=0

By quadratic formula :

⇒ sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}

⇒ sinx = \frac{-1 \pm3}{4}

⇒ sinx = \frac{1}{2} , sinx =-1

⇒ sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}

⇒ x=\frac{\pi}{6} , x=\frac{3\pi}{2}

But at x=\frac{3\pi}{2} we have equation undefined as cos\frac{3\pi}{2}=0 . Hence only solution is :

⇒ x=\frac{\pi}{6}

Since , sin(\pi -x)=sinx

⇒ x=\pi -\frac{\pi}{6} = \frac{5\pi}{6}

Now , General Solution is given by :

⇒ x=2k\pi + \frac{\pi}{6}  , x=2k\pi + \frac{5\pi}{6}

Therefore , Solution to equationcosxtanx - 2 cos^2 x=-1 for all real values of x is  x=2k\pi + \frac{\pi}{6}  , x=2k\pi + \frac{5\pi}{6} .

3 0
3 years ago
Find an equivalent ratio for 22/55 and then write the proportion
lutik1710 [3]
\frac{22}{55} = \frac{2}{5} = .4
7 0
3 years ago
Read 2 more answers
Please help me fast I still nee to finish 2 more ixl's by monday!!!!
sleet_krkn [62]

Answer:No

Step-by-step explanation:

Given system of equation is:

2x + 3 = y

2x + y = 15

To check whether (2,7) is solution to this system or not, we will put x=2 and y=7 in both equations.

Putting x=2 and y=7 in Eqn 1

2(2) + 3 = 7

4 + 3 = 7

7 = 7

Thus the ordered pair satisfies the equation

Putting x=2 and y=7 in Eqn 2

2(2) + 7 = 15

4 + 7 = 15

11 ≠ 15

The ordered pair do not satisfy the second equation.

Hence,

(2,7) is not a solution to the given system of equations.

3 0
3 years ago
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