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3 years ago

Is 2/3 greater than 2/5?

1 answer:

7 0

Yes. 2/3 is greater than 2/5. You can check this by cross multiplication or easier just look at the denominator and numerator. In this case the numerator is the same so it's easier in a sense that you need to look at the denominator. Since the denominator 3 is close to the numerator 2 it shows that it's almost a whole unlike the other fraction. You can also convert each fraction to decimals and compare it which is also easy. Just divide the numerator by the denominator and you've got a decimal. Hope this helps!

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Mr Stephen saved 350 rupees per month how much money will he save in 3 years

xz_007 [3.2K]

Answer:

the answer to that question is 12,600 rupees

4 0

1 year ago

There are 24 pictures on a roll of film. Adelle had 84 pictures from her trip home. She said that 12 other pictures were spoiled

Anna71 [15]

Answer:

Total pictures = 84+12 = 96

roll of films = 96 / 24 = 4

she used 4 rolls

7 0

2 years ago

What are the coordinates grapging x=3 and y=-2x+1

marusya05 [52]

Answer: -5

First, coordinates are (x, y). You’re x is 3, so all you need to do it plug in x into your algebraic equation to find y. Then just plug both into (x, y) and you have your coordinates.

y=-2(3)+1
y=-6+1
y=-5

7 0

3 years ago

calculate the unit rate of change for each linear function using the formula. (4,9) (8,12) (16,18) (32,30)

jenyasd209 [6]

Answer:

The unit rate of change is of $\frac{3}{4}$

Step-by-step explanation:

We are given a set of points (x,y).

To find the unit rate of change, we take two points, and divide the change in y by the change in x.

Points (4,9) and (8,12)

Change in y: 12 - 9 = 3

Change in x: 8 - 4 = 4

Unit rate of change: $\frac{3}{4}$

7 0

3 years ago

Lerola and her younger sister Kiara are jogging around a circular track. Lerola jogs far enough from the center of the circle th

xxTIMURxx [149]

Circumference of circular track, C = 0.5 miles = 0.5×5280 feet = 2640 feet.

We know, circumference in circle is given by :

$C = 2\pi r$

( Here, r is radius i.e distance of centre from track )

Putting values in above equation :

2 × 3.14 × r = 2640

6.28 × r = 2640

r = 420.38 feet

Therefore, distance between centre and track is 420.38 feet .

Hence, this is the required solution.

4 0

2 years ago