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Sonja [21]
2 years ago
9

What will $82,000 grow to be in 11 years if it is invested today at 8% and the interest rate is compounded monthly

Mathematics
1 answer:
Mariana [72]2 years ago
7 0

Answer:

Well the answer would be 865,920. Hope this helped! this is the way i learned it so if its wrong i'm super sorry!

Step-by-step explanation:

I = p x r x t

I = 82,000 x 8 x 11yrs

BUT WAIT! this is MONTHLY, so convert 11 x 12 = 132 and then move 8 back 2 spaces = 0.08 so the correct equation is

I = 82,000 x 0.08 x 132

I = 865,920

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HELP I GIVE BIG BRAIN!!! see attachment
Evgesh-ka [11]
Evet canım çok teşekkür ederim canım benim için çok teşekkür ederimmm
4 0
2 years ago
A. Do some research and find a city that has experienced population growth.
horrorfan [7]
A. The city we will use is Orlando, Florida, and we are going to examine its population growth from 2000 to 2010. According to the census the population of Orlando was 192,157 in 2000 and 238,300 in 2010. To examine this population growth period, we will use the standard population growth equation N_{t} =N _{0}e^{rt}
where:
N(t) is the population after t years
N_{0} is the initial population 
t is the time in years 
r is the growth rate in decimal form 
e is the Euler's constant 
We now for our investigation that N(t)=238300, N_{0} =192157, and t=10; lets replace those values in our equation to find r:
238300=192157e^{10r}
e^{10r} = \frac{238300}{192157}
ln(e^{10r} )=ln( \frac{238300}{192157} )
r= \frac{ln( \frac{238300}{192157}) }{10}
r=0.022
Now lets multiply r by 100% to obtain our growth rate as a percentage:
(0.022)(100)=2.2%
We just show that Orlando's population has been growing at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

B. Here we will examine the population decline of Detroit, Michigan over a period of ten years: 2000 to 2010.
Population in 2000: 951,307
Population in 2010: 713,777
We know from our investigation that N(t)=713777, N_{0} =951307, and t=10. Just like before, lets replace those values into our equation to find r:
713777=951307e^{10r}
e^{10r} = \frac{713777}{951307}
ln(e^{10r} )=ln( \frac{713777}{951307} )
r= \frac{ln( \frac{713777}{951307}) }{10}
r=-0.029
(-0.029)(100)= -2.9%.
We just show that Detroit's population has been declining at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

C. Final equation from point A: N(t)=192157e^{0.022t}.
Final equation from point B: N(t)=951307e^{-0.029t}
Similarities: Both have an initial population and use the same Euler's constant.
Differences: In the equation from point A the exponent is positive, which means that the function is growing; whereas, in equation from point B the exponent is negative, which means that the functions is decaying.

D. To find the year in which the population of Orlando will exceed the population of Detroit, we are going equate both equations N(t)=192157e^{0.022t} and N(t)=951307e^{-0.029t} and solve for t:
192157e^{0.022t} =951307e^{-0.029t}
\frac{192157e^{0.022t} }{951307e^{-0.029t} } =1
e^{0.051t} = \frac{951307}{192157}
ln(e^{0.051t})=ln( \frac{951307}{192157})
t= \frac{ln( \frac{951307}{192157}) }{0.051}
t=31.36
We can conclude that if Orlando's population keeps growing at the same rate and Detroit's keeps declining at the same rate, after 31.36 years in May of 2031 Orlando's population will surpass Detroit's population.

E. Since we know that the population of Detroit as 2000 is 951307, twice that population will be 2(951307)=1902614. Now we can rewrite our equation as: N(t)=1902614e^{-0.029t}. The last thing we need to do is equate our Orlando's population growth equation with this new one and solve for t:
192157e^{0.022t} =1902614e^{-0.029t}
\frac{192157e^{0.022t} }{1902614e^{-0.029t} } =1
e^{0.051t} = \frac{1902614}{192157}
ln(e^{0.051t} )=ln( \frac{1902614}{192157} )
t= \frac{ln( \frac{1902614}{192157}) }{0.051}
t=44.95
We can conclude that after 45 years in 2045 the population of Orlando will exceed twice the population of Detroit. 

  
8 0
3 years ago
Ben the camel drinks tea (so classy!). He drinks 405 liters of tea every 2 days. How many liters of tea does Ben drink every 6 d
Hoochie [10]
6/2=3
405*3= 1,215
hope this helps
7 0
2 years ago
Find the volume of this square<br> based pyramid.<br> 10 cm<br> 8 cm<br> 8 cm<br> V = [?] cm3
oksano4ka [1.4K]

Answer:

213.3

Step-by-step explanation:

The volume of a pyramid is 1/3 base times height.

Using this formula, our square base is 8*8, or 64 square units.

Multiplying that by the height, 10. We get 64*10, 640.

Finally dividing by 3, we have 213.3333333333...

Rounding that to the nearest tenth, 213.3.

3 0
3 years ago
The perimeter of the rectangle below is 65 inches.
Tems11 [23]

Answer:

A :-) Given -

perimeter = 65 inches

Side ‘a’ = 2x

Side ‘b’ = 3 1 by 4x + 1

Solution -

Perimeter = 65

= a + b = 65

= 2x + 3 1 by 4x + 1 = 65

( 3 1 by 4 = 4 x 3 + 1 = 12 + 1 by 4

= 13 by 4 )

= 2x + 13 by 4x + 1 = 65

= 2x + 13 by 4x = 65 - 1

= 2x + 13 by 4x = 64

= 15 by 4 x = 64

= x = 64 x 4 by 15

= x = 256 by 15

= x = 17.06

.:. The value of x = 17.06.

7 0
3 years ago
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