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VMariaS [17]
4 years ago
13

A coordinate grid with a line labeled negative 3 x plus StartFraction one-half EndFraction y equals negative 3 and passes throug

h the points (1, 0) and (0, negative 6).
What value of b will cause the system to have an infinite number of solutions?

y = 6x – b

–3x + StartFraction one-half EndFractiony = –3

b =

2
4
6
8
Mathematics
2 answers:
natali 33 [55]4 years ago
5 0

Answer:

its option C,   6

Step-by-step explanation:

tensa zangetsu [6.8K]4 years ago
3 0

Answer: C

Step-by-step explanation:

Given that the line -3x + y/2 = -3 passes through the points (1, 0) and (0, -6).

First rearrange the equation

-3x + y/2 = -3

Y = 2( 3x - 3 )

Y = 6x - 6 ..... (1)

Also, the slope of points (1, 0) and (0, -6). Will be

M = ( -6 - 0 )/( 0 - 1 )

M = -6/-1

M = 6

Using general linear equation

Y = MX + C

Let Y = 0 and X = 1

0 = 6(1) + C

C = -6

Substitutes C back into the equation

Y = 6x - 6 ...... (2)

The value of b that will cause the system to have infinitely many number of solutions is 6

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Dmitry [639]

Answer:

Given n collinear points, 2(n -1) or 2n - 2 rays can be named

Step-by-step explanation:

When we talk of collinear points, we mean points that lie on the same straight line.

For 3 collinear points we can have 4 rays

For 4 collinear points, let’s say ABCD

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The rays are AB BA BC CB CD and DC making a total of 6

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So what pattern do we notice?

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So using the pattern

n rays = 2n - 2 rays or simply 2(n - 1) rays

8 0
4 years ago
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We have 
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Step-by-step explanation:

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