Answer:
As the described function, we want to find vertical asymtotes, we find the value of x so that the denominator is equal to 0.
Here, (x - 2)(x + 6) = 0
=> x = 2, x =-6
=> Option C is correct.
Hope this helps!
:)
The answer is $45 it wasn’t that hard
Remember
a^3-b^3=(a-b)(a^2+ab+b^2)
(11x)³-(2y)³=(11x-2y)(121x²+22xy-4y²)
(5 + 2i)(1 + 3i)
5 * 1 = 5
5 * 3 = 15i
2i * 1 = 2i
2i * 3i = 6i^2
So we have...
5 + 15i + 2i + 6i^2
5 + 17i + 6i^2
In order....
6i^2 + 17i + 5
2 would be the correct answer ;-)))) (1 on top?)
