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3 years ago

6

F = C + 32, for C Select one: A. C = (F - 32) B. C = C. C = (F - 32) D. C =

2 answers:

Rom4ik [11]3 years ago

7 0

Answer:

A. C= (F-32)

Step-by-step explanation:

F = C + 32

make c the subject of formula

F = C + 32

subtract 32 from both sides

F-32 = C + 32-32

F-32 = C

Lerok [7]3 years ago

6 0

Answer:

Option A is correct :

C = F - 32

Step-by-step explanation:

F = C + 32

We are solving for C.

Let's subtract 32 from both sides:

F - 32 = C + 32 - 32

F - 32 = C + 0

F - 32 = C

We can also rewrite it as:

C = F - 32

C = (F - 32)

Math is fun

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The point slope form of the equation of the line that passes through (-5-1) and (10.-7) is

Natalka [10]

Answer:

The standard form of the equation for this line can be:

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Start by finding the slope of this line.

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$\displaystyle \text{Slope} = \frac{y_{1} - y_{0}}{x_{1} - x_{0}}$ .

For this line,

$\displaystyle \text{Slope} = \frac{(-1) - (-7)}{(-5) - 10} = -\frac{2}{5}$ .

Find the slope-point form of this line's equation using

$\displaystyle \text{Slope} = -\frac{2}{5}$ , and
The point $(-5, -1)$ (using the point $(10, -7)$ should also work.)

The slope-point form of the equation of a line

with slope $m$ and
point $(x_{0}, y_{0})$

should be $l:\; y - y_{0} = m(x - x_0)$ .

For this line,

$\displaystyle m = -\frac{2}{5}$ , and
$x_0 = -5$ , and
$y_0 = -1$ .

The equation in slope-point form will be

$\displaystyle l:\; y - (-1) = -\frac{2}{5}(x - (-5))$ .

The standard form of the equation of a line in a cartesian plane is

$l: \; ax + by = c$

where

$a$ , $b$ , and $c$ are integers. $a \ge 0$ .

Multiply both sides of the slope-point form equation of this line by $5$ :

$l:\; 5 y + 5 = -2x -10$ .

Add $(2x-5)$ to both sides of the equation:

$l: \; 2x + 5y = -15$ .

Therefore, the equation of this line in standard form is $l: \; 2x + 5y = -15$ .

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