Answer:
980,100
Explanation:
let the recessive condition (aa) be represented as q² which is the genotypic frequency = 100/1,000,000 = 0.0001
allelic frequency of a = q = √q² = √0.0001 = 0.01. thus q = 0.01
From the formula p + q = 1 where p is the allelic frequency of A.
since q = 0.01
p = 1 - 0.01 = 0.99. The allelic frequency of A (p) = 0.99
p² = 0.99² = 0.9801. Genotypic frequency of AA= 0.9801
= 0.9801 x 1,000,000 = 980,100 individuals with AA (homozygous normal)
For 2pq genotypic frequency for hetrozygous (Aa).
Using the formula p² + 2pq + q² = 1. Since p² = 0.9801 and q² = 0.0001
2pq = 1 - (p² + q²)
= 1 - (0.9801 + 0.0001)
= 1 - (0.9802)
= 0.0198 = 0.0198 x 1,000,000 = 19,800 individuals with Aa
Transpiration is when the plant loses water through its leaves.Respiration is when the plant breaks down the sugar in its cell to release energy
Respiration and Photosynthesis
Gaseous exchange is fundamental in aerobic organisms because oxygen is required to carry out cellular respiration.
<h3>What is cellular respiration?</h3>
Cellular respiration is a series of chemical reactions by which aerobic organisms interchange oxygen and carbon dioxide with their surrounding environment.
During cellular respiration, oxygen is consumed to generate ATP and carbon dioxide is released.
In conclusion, gaseous exchange is fundamental in aerobic organisms because oxygen is required to carry out cellular respiration.
Learn more about cellular respiration here:
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