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Helga [31]
3 years ago
13

What is log3 6 + log3 13.5

Mathematics
1 answer:
Luden [163]3 years ago
6 0
Log base3 (6*13.5)
log base 3 (81)
log base 3 (3)^4
4 log base 3 (3)
4 * 1 = 4

First condense the logs by using the product rule.
Next rewrite 81 in terms of 3.
Use the power rule and bring the 4 to the front.
log base 3 (3) = 1
Which leaves 4 * 1 = 4
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ABC is a tangent to the circle below. O is the centre of the circle. Work out the size of angle 0. Give reasoning to justify you
Delvig [45]

Answer:

Θ = 46°

Step-by-step explanation:

the angle between a tangent and a radius at the point of contact is 90° , so

∠ ABO = 90°

since OB = OD ( radii of circle ) then Δ BOD is isosceles and

∠ OBD = ∠ ODB = 22°

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∠ AOB is an exterior angle of the triangle , then

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2 years ago
Solve and graph the following inequality: 3(7x+17) &gt; -19 + 14x
love history [14]

Answer:

Solving the inequality we get: \mathbf{x>-7}

Step-by-step explanation:

We need to solve and graph the inequality 3(7x+17) > -19 + 14x

Solving:

3(7x+17) > -19 + 14x

Step 1: Multiply  3 with terms inside the bracket

21x+51 > -19 + 14x

Step 2:Subtracting 51 on both sides

21x+51-51 > -19 + 14x-51\\21x>14x-70\\

Step 3: Subtract 14x on both sides

21x-14x>+14x-70-14x\\7x>-70

Step 4: Divide both sides by 7

\frac{7x}{7}>\frac{-70}{7}\\x>-10

Solving the inequality we get: \mathbf{x>-7}

The graph is attached in the figure below.

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The answer should be 652.2
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