Find the equation of the linear relationship.

A car rental company charges a one-time application fee of 20 dollars, 45 dollars per day, and 15 cents per mile for its cars. W

crimeas [40]

Answer:

$C(d,m) = 20 + 45d + 0.15m$

Step-by-step explanation:

In this problem, we have that the cost of renting a car C is a function of the number of days d, and the number of miles driven, m.

There is also a fixed cost F.

So the equation for the cost of renting a car is:

$C(d,m) = F + a*d + b*m$

In which a is the daily cost and b is the cost per mile.

A car rental company charges a one-time application fee of 20 dollars, 45 dollars per day, and 15 cents per mile for its cars.

This means that $F = 20, a = 45, b = 0.15$

Write a formula for the cost, C, of renting a car as a function of the number of days, d, and the number of miles driven, m.

$C(d,m) = 20 + 45d + 0.15m$

6 0

3 years ago

Which pair of angles are adjacent angles?

Sloan [31]

Your answer is B. 1 and 3.
This is because adjacent angles are angles that could form one angle if the line inbetween them was removed, which means they have a common side. Angles 1 and 3 are the only angles out of the options that have a common side, so they must be the answer.

I hope this helps!

7 0

3 years ago

The cost of belonging to a gym can be modeled by C(m)= 50m + 79.50, where C(m) is the total cost for m months of membership. Sta

erik [133]

Answer:

The slope is 50, which is the cost per month of the gym membership, and 79.50 is the y intercept. It represents the initial cost to join the gym.

Step-by-step explanation:

C(m)= 50m + 79.50,

This is written in the form y= mx+b where m is the slope and b is the y intercept.

The slope is 50, which is the cost per month of the gym membership, and 79.50 is the y intercept. It represents the initial cost to join the gym.

3 0

4 years ago

Write as a single logarithm

Anettt [7]

ANSWER

$c. \ln( \frac{2 {x}^{3} }{3y})$

EXPLANATION

We want to write

$ln(2x) + 2 ln(x) - ln(3y)$

as a single logarithm.

Use the power rule to rewrite the middle term:

$n \: ln(a) = ln( {a}^{n} )$

$ln(2x) + ln( {x}^{2} ) - ln(3y)$

Use the product rule to obtain:

$ln(a) + ln(b) = ln(ab)$

$ln(2x \times {x}^{2} )- ln(3y)$

$ln(2{x}^{3} )- ln(3y)$

Apply the quotient rule:

$ln(a) - ln(b) = ln( \frac{a}{b})$

$ln(2{x}^{3} )- ln(3y) =\ln(\frac{2 {x}^{3} }{3y})$

7 0

3 years ago

The? half-life of a radioactive substance is 20 years. If you start with some amount of this? substance, what fraction will rema

yarga [219]

$\bf \textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\\ t=\textit{elapsed time}\dotfill &120\\ h=\textit{half-life}\dotfill &20 \end{cases} \\\\\\ A=P\left( \frac{1}{2} \right)^{\frac{120}{20}}\implies A=P\left( \frac{1}{2} \right)^6\implies A=P\left( \cfrac{1^6}{2^6} \right)\implies A=\cfrac{1}{64}P$

6 0

4 years ago