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GrogVix [38]
3 years ago
9

Write ln (4/9) in terms of ln 2 and ln 3.

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
3 0

Answer taken away. (Sorry, I put the wrong one)

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PLS HELP ME, PLS THIS IS DUE FIRST CORRECT ANSWER GETS BRAINLIEST​
shusha [124]

Answer:

A. 49 + 16 (t - 1)

Step-by-step explanation:

Plug in t = 1 to test for the first hour:

49+16(1-1)=49+16(0)=49

Test as many values as you like, but testing t = 5:

49+16(5-1)=49+16(4)=49+64=113

You can see that plugging in just a few values confirms the answer.

8 0
2 years ago
Bob needs one hour to roke the leaves, It takes George 1/2 an hour to do 1
Mandarinka [93]

Step-by-step explanation:

30 minutes because you can just subtract Geoge's time

7 0
2 years ago
Find the value of y...​
soldier1979 [14.2K]

Answer:

y=0

Step-by-step explanation:

Rewrite Evaluate Powers:

33^{2y-1}+3^{-1}+2*3^{y}*3^{-1}=1

Calculate:

(3^{y})^{2}*\frac{1}{3} +2*3^{y}*\frac{1}{3}=1

Solve using substitution:

(3^{y})^{2}*\frac{1}{3} +\frac{2}{3} *3^{y}=1     t=3^{y}

Solve the equation for t:

t^{2}*\frac{1}{3}+\frac{2}{3}t=1

t=-3

t=1

Substitute back to t=3^y

3^y=-3

3^y=1

y∉R

3^{y}=1

y=0

5 0
2 years ago
A rectangular lamina of uniform density is situated with opposite corners at (0,0) and (15,4). calculate its radii of gyration a
Sphinxa [80]
First, you have to find the moment of inertia along the x and y axes. Constant density is denoted as k.


I_{x}= \int\limits^15_0\int\limits^4_0 {k y^{2} } \, dx  dy= \frac{1}{3}k (15-4)^4=4880.33k

I_{y}= \int\limits^15_0\int\limits^4_0 {k x^{2} } \, dx  dy= \frac{1}{3}k (15-4)^4=4880.33k

Then, the radii of gyration for

x = √[I_x/m]
y = [I_y/m]

where m = k(15-4)² = 121k. Then,

x = y = [4880.33k/121k] = 40.33

I hope I was able to help you. Have a good day.
7 0
3 years ago
Find the unknown side length. Round to the nearest tenth a=5 b=? C=25
ZanzabumX [31]

Answer: 5

Step-by-step explanation:

6 0
3 years ago
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