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GrogVix [38]
3 years ago
9

Write ln (4/9) in terms of ln 2 and ln 3.

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
3 0

Answer taken away. (Sorry, I put the wrong one)

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She'll have 17 with a remainder, just divide 139 by 8.
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Find the fractional side lengths of a rectangle that has a perimeter of 64 5/6 inches.
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Write the point slope form of the equation of the line through (4,3) and (-2,-4)​
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3 years ago
The nut shack sells cashews for $6.00 per pound and Brazil nuts for $5.00 per pound. How much of each type should be used to mak
Kay [80]

Answer:

Number of pounds of cashews = x = 14.96 pounds

Number of pounds of Brazil nuts = y = 19.04 pounds

Step-by-step explanation:

Let us represent:

Number of pounds of cashews = x

Number of pounds of Brazil nuts = y

The nut shack sells cashews for $6.00 per pound and Brazil nuts for $5.00 per pound. How much of each type should be used to make a 34 pound mixture that sells for $5.44 per pound

Our system of equations is given as:

x + y = 34...... Equation 1

x = 34 - y

6x + 5y = 34 × 5.44

6x + 5y = 184.96.......Equation 2

Ww substitute : 34 - y for x in Equation 2

6(34 - y) + 5y = 184.96

204 - 6y + 5y = 184.96

Collect like terms

- 6y + 5y = 184.96 - 204

-y = -19.04

y = 19.04 pounds

Solving for x

x = 34 - y

x = 34 - 19.04

x = 14.96 pounds

Number of pounds of cashews = x = 14.96 pounds

Number of pounds of Brazil nuts = y = 19.04 pounds

7 0
2 years ago
More on Areas. Farmer Jones, and his wife, Dr. Jones, both mathematicians, decide to build a fence in their field to keep the sh
Olin [163]

Answer:

Area covered by the fences will be 16.1 unit²

Step-by-step explanation:

Let the first parabola is represented by the function f(x) = 6x²

and second parabola by g(x) = x² + 9

point of intersection of the graphs will be determined when f(x) = g(x)

6x² = x² + 9

5x² = 9

x² = 1.8

x = ± 1.34

Now we will find the area between these curves drawn on the graph.

Area = \int_{-1.34}^{1.34}[f(x)-g(x)]dx=\int_{-1.34}^{1.34}[6x^{2}-(x^{2}+9)]dx

= \int_{-1.34}^{1.34}(5x^{2}-9)dx

= [\frac{5}{3}x^{3}-9x]_{-1.34}^{1.34}

= [\frac{5}{3}(-1.34)^{3}-9(-1.34)-\frac{5}{3}(1.34)^{3}+9(1.34)]

= [-4.01+12.06-4.01+12.06]

= 16.1 unit²

6 0
3 years ago
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