The monthly failure rate is q = 5% = 0.05
The monthly pass rate is p = 1 - q = 0.95
We want to determine the probability of 12 passes in 12 consecutive months for a student.
P(12 of 12 successes) = ₁₂C₁₂ p¹² q⁰ = 0.95¹² = 0.5404.
Therefore if we have 100 students, the number that gets through 12 consecutive months is
100*005404 = 54 students.
Answer: 54 students are left after 12 months.
One integer is x
another integer is y
x=8y
xy=288
(8y)(y)=288
8y^2=288
Divide both sides by 8
y^2= 36
The square root of 36 is 6
y=6
x=8y = 8(6) = 48
x=48
Answer:

Step-by-step explanation:
Hi there! I'm glad I was able to help you solve this equation!
Let's start by simplifying both sides of the equation. It's easier to solve it this way!

Distribute:


Combine 'like' terms:


Next, you'll want to add 36 to both sides of the equation.


Finally, divide both sides by
.


I hope this helped you! Leave a comment below if you have any further questions! :)
Based on the weight and the model that is given, it should be noted that W(t) in radians will be W(t) = 0.9cos(2πt/366) + 8.2.
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How to calculate the radian.</h3>
From the information, W(t) = a cos(bt) + d. Firstly, calculate the phase shift, b. At t= 0, the dog is at maximum weight, so the cosine function is also at a maximum. The cosine function is not shifted, so b = 1.
Then calculate d. The dog's average weight is 8.2 kg, so the mid-line d = 8.2. W(t) = a cos t + 8.2. Then calculate a, the dog's maximum weight is 9.1 kg. The deviation from the average is 9.1 kg - 8.2 kg = 0.9 kg. W(t) = 0.9cost + 8.2
Lastly, calculate t. The period p = 2π/b = 2π/1 = 2π. The conversion factor is 1 da =2π/365 rad. Therefore, the function with t in radians is W(t) = 0.9cos(2πt/365) + 8.2.
Learn more about radians on:
brainly.com/question/12939121