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Arte-miy333 [17]
3 years ago
8

If x^2 = 49, then x^-2 =

Mathematics
2 answers:
kenny6666 [7]3 years ago
6 0
-49
When you solve x^2 x=7 because 7x7=49. All that changes in the second equation is there is a negative sign so x^-2=-49
I would recommend if you need help on math like this download Photomath.
Natalija [7]3 years ago
4 0

Answer:

0.001665973

Step-by-step explanation:

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Mashcka [7]

Answer:

3.140

Step-by-step explanation:

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5 0
2 years ago
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Simplify the expression -4x^2(3x − 7).
satela [25.4K]

Answer:

Step-by-step explanation:

Simplify the expression -4x^2(3x − 7).

A. -12x^3 + 28

<h2>B. -12x^3 + 28x^2<= your answer</h2>

C. -12x^3 − 28

D. -12x^3 − 28x^2

5 0
2 years ago
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Mr. Abbot buys eight boxes of granola bars for a party each box has nine granola bars after the parties there are 39 bars left h
Fittoniya [83]

Answer:

no of box multiply by no of granolas then subtract 39 bars

8×9=72

72-39=33

7 0
3 years ago
Answer this question pls!! (Will give Brainliest)
AnnyKZ [126]

Answer:

D. y = 12.5x + 15

Step-by-step explanation:

Using the values provided in the table, the only equation that would be valid would be the following...

y = 12.5x + 15

That is because if we substitute any value provided in the table for x , this equation will correctly output the y value shown in the table for the attached x-value. For example, in the table 5 nights (x = 5) should have a total cost of 77.5 (y = 77.5)... Therefore, if we substitute 5 for x in the function it should give  us 77.5 which it does.

y = 12.5(5) + 15

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3 0
3 years ago
Find an equation for the line tangent to the curve at the point defined by the given value of t. Also, find the value of d^2y/dx
nikdorinn [45]

Answer:

Differentiation will give you the gradient for the tangent at any point, and you use the product rule whenever a function can be thought of as two functions multiplied together.

If

f

(

x

)

=

g

(

x

)

×

h

(

x

)

then

f

'

(

x

)

=

g

'

(

x

)

h

(

x

)

+

g

(

x

)

h

'

(

x

)

so if

y

=

x

×

sin

x

then

d

y

d

x

=

1

×

sin

x

+

x

×

cos

x

=

sin

x

+

x

cos

x

We know that

x

=

π

2

, so the gradient is

m

=

sin

(

π

2

)

+

π

2

cos

(

π

2

)

=

1

+

π

2

×

0

=

1

Therefore, we can say that

y

=

m

x

+

c

y

=

(

1

)

x

+

c

y

=

x

+

c

So all we really need to find now is the value for

c

, the

y

intercept. We do this by working out a point

(

x

,

y

)

on the graph. We are already given that

x

=

π

2

, so

y

=

x

sin

x

=

π

2

sin

(

π

2

)

=

π

2

×

1

=

π

2

∴

(

x

,

y

)

=

(

π

2

,

π

2

)

Now we substitute this into the equation we already have for the tangent,

y

=

x

+

c

,

(

x

,

y

)

=

(

π

2

,

π

2

)

π

2

=

π

2

+

c

c

=

π

2

−

π

2

=

0

∴

y

=

x

+

c

=

x

+

(

0

)

=

x

which means the tangent to the curve

y

=

x

sin

x

at

(

π

2

,

π

2

)

is simply

y

=

x

.

3 0
2 years ago
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