If x^2 = 49, then x^-2 =

2 answers:

6 0

-49
When you solve x^2 x=7 because 7x7=49. All that changes in the second equation is there is a negative sign so x^-2=-49
I would recommend if you need help on math like this download Photomath.

Natalija [7]3 years ago

4 0

Answer:

0.001665973

Step-by-step explanation:

You might be interested in

Evaluate x (5-y) ; use x=6,and y=1

Zolol [24]

Answer:

Step-by-step explanation:

x (5-y)

Let x=6,and y=1

6(5-1)

PEMDAS says parentheses first

6(4)

6 0

3 years ago

Hello my daughter needs help on her homework Thi is her question

givi [52]

Answer:

Athena = 10,265 km

Vesta = 102,650 km

Juno = 102,650 km

Ceres = 2,053,000 km

Apollo = 1,026,500 km

Step-by-step explanation:

Athena = 20,530 / 2 = 10,256

From there, you can work out the rest by multiplying accordingly.

Hope this helps and made sense! :)

6 0

3 years ago

Situation:A researcher in North America discoversa fossile that contains 65% of its originalamount of C-14..-ktN=NoeNo inital am

zheka24 [161]

SOLUTION

We have been given the equation of the decay as

$\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}$

So we are looking for the time

Plugging the values into the equation, we have

$\begin{gathered} N=N_0e^{-kt} \\ 0.65N_0=N_0e^{-0.0001t} \\ e^{-0.0001t}=\frac{0.65N_0}{N_0} \\ e^{-0.0001t}=0.65 \end{gathered}$

Taking Ln of both sides, we have

$\begin{gathered} ln(e^{-0.000t})=ln(0.65) \\ -0.0001t=ln(0.65) \\ t=\frac{ln(0.65)}{-0.0001} \\ t=4307.82916 \end{gathered}$

Hence the answer is 4308 to the nearest year

8 0

11 months ago

About 6% of the population has a particular genetic mutation. 600 people are randomly selected. find the standard deviation for

Rina8888 [55]

Assume a binomial distribution. Then the mean of the distribution is $np$ , where $n$ is the number of people taken in a sample and $p$ is the probability of the mutation occurring in any given person, and the standard deviation is $\sqrt{np(1-p)}$ . Then in this case, the standard deviation is $\sqrt{600(0.06)(0.94)}\approx5.82$ .