The given sequence is
a₁ = 29
a₂ = 39
a₃ = 49
a₄ = 59
This sequence is an arithmetic sequence. Th first term is a₁ = 29, and the common difference is d= 10.
The n-th term is

The 33-rd termis
a₃₃ = 29 + (33 - 1)*10
= 29 + 320
= 349
Answer: a₃₃ = 349
Answer:
you would put a point on 10 then an arrow up to 20
Step-by-step explanation:
Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth.
krok68 [10]
Answer:
Mean = 51.4.
Mode = 49.
Median = 52.
Range = 6.
Step-by-step explanation:
Mean = Sum of all observations / Number of observations.
Mean = (49+49+54+55+52+49+52)/7
Mean = 360/7
Mean = 51.4 (to the nearest tenth).
Mode = The most repeated values = 49 (repeated 3 times).
Range = Largest Value - Smallest Value = 55 - 49 = 6.
Median = The central value of the data.
First, arrange the data in the ascending order: 49, 49, 49, 52, 54, 55, 55.
It can be seen that the middle value is 52. Therefore, median = 52!!!
Answer:
m∠T = 72°
m∠U = 54°
Step-by-step explanation:
Property of an isosceles triangle,
Opposite angles of two equal sides of an isosceles triangle are equal in measure.
By this property, in the given triangle STU,
Since, ST ≅ TU,
m∠S = m∠U = 54°
Since, sum of interior angles of a triangle is 180°
m∠T + m∠S + m∠U = 180°
m∠T + 54° + 54° = 180°
m∠T = 180° - 108°
m∠T = 72°