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tangare [24]
4 years ago
14

A local bakery buys their flour in bulk. The relationship between the cost of the flour and its weight is shown in the graph bel

ow.
Is the relationship shown a direct variation? Explain your reasoning using complete sentences.
The point (1, 0.75) is on this graph. What does this ordered pair represent?
Approximately how much does the bakery pay for 40 pounds of flour?

Mathematics
1 answer:
Nataly [62]4 years ago
8 0
The relationship shown for the flour and the cost is that of a direct variation because the graph is a straight line, noting that the increase of one variable causes also the increase to the value of the other. The point (1, 0.75) means that every pound of flour costs 0.75 dollar. From the graph given, the bakery will have to pay approximately $30 for 40 pounds of flour. 
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What is the image point of (1,-2)after a translation right 4 units and down 4 units?
den301095 [7]

By applying the concept of translation, we conclude that the <em>image</em> point of (1, - 2) is equal to the point (5, - 6).

<h3>What is the image of a point by rigid translations?</h3>

In this problem we have a point set in a <em>Cartesian</em> plane, which has to be translated to determine the coordinates of a <em>resulting</em> point. Translations are examples of <em>rigid</em> transformations, these are, transformations applied on <em>geometric</em> loci such that <em>Euclidean</em> distance is conserved.

Vectorially speaking, translations are modelled by the following formula:

P'(x, y) = P(x, y) + T(x, y)      (1)

Where:

  • P(x, y) - Original point
  • P'(x, y) - Resulting point
  • T(x, y) - Translation vector

If we know that P(x, y) = (1, - 2) and T(x, y) = (4, - 4), then the resulting point is:

P'(x, y) = (1, - 2) + (4, - 4)

P'(x, y) = (5, - 6)

By applying the concept of translation, we conclude that the <em>image</em> point of (1, - 2) is equal to the point (5, - 6).

To learn more on rigid transformations: brainly.com/question/1761538

#SPJ1

5 0
2 years ago
What is a solution to the following system of equations?<br><br> x2 + y2 = 13 <br> 2x - y = 4
patriot [66]
A solution to the equation is (-3,-2)
5 0
3 years ago
A plane flying over the ocean is on course to land on an aircraft carrier. The diagonal distance between the plane and the aircr
fomenos

Answer:

the plane's current height above the ocean is 3.42 miles

Step-by-step explanation:

Given that the diagonal distance between the plane and the aircraft carrier is 10 miles.

What we need to find is the vertical distance between the plane and the aircraft carrier which is the plane's current height above the ocean. This can be gotten using sine rule.  

For sine rule, you need a side and its opposite angle. For this question the triangle formed is a right angle triangle with diagonal distance, vertical distance and horizontal distance.

let a = diagonal distance = 10 miles

let the opposite angle to the diagonal distance be A = 90° (right angle)

let the vertical distance = b

let the opposite angle to the vertical distance be B = 20°

Sine rule states that    \frac{a}{sin(A)}  =  \frac{b}{sin(B)}

∴   \frac{10}{sin(90)}  =  \frac{b}{sin(20)}

b  =  sin(20)\frac{10}{sin(90)}

b  =  0.342*\frac{10}{1}

⇒ b = 3.42 miles

Therefore the plane's current height above the ocean is 3.42 miles

4 0
3 years ago
Rosa recorded the height (in centimeters) of a pea plant over a 10-day period for a science experiment. Please help me with this
katrin [286]

Answer:

option a)

y = m(0.5) + 1.8

Step-by-step explanation:

Equation

<h3>y = mx + c</h3>

represent the equation of straight line

here m = gradient of straight line

         c = y-intercept

First find the gradient of the graph

<h3>m = y2 - y1 / x2 - x1</h3>

    = 4 - 3 / 4 - 2

    = 1 / 2

Put the values in the equation of straight line

y =mx + c

4 = 1/2(4) + c

c = 2

y = 1/2x + 2

which is approximately equal to y = 0.5x + 1.8

7 0
3 years ago
Use the given minimum and maximum data​ entries, and the number of​ classes, to find the class​ width, the lower class​ limits,
Gennadij [26K]

Using proportions and the information given, it is found that:

  • The class width is of 14.375.
  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

  • Minimum value is 19.
  • Maximum value is of 134.
  • There are 8 classes.
  • The classes are all of equal width, thus the width is of:

W = \frac{134 - 19}{8} = 14.375

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

6 0
3 years ago
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