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Goshia [24]
4 years ago
14

the students in high school enter school between 9:45am to 10am. the timing of the 400 students entering the school are normally

distributed. with a mean of 9:55 and a standard deviation of 1 minute. how many students enter before 9:55am​
Mathematics
1 answer:
bonufazy [111]4 years ago
4 0

Answer:64 students

Step-by-step explanation:

using the empirical rule, we know that 34% of a normal distribunion is below the mean but above 1 standard deviation. This means that 16% of the students enter before 9:55. Take 16% of 400 and you get the amount of students in before 9:55

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For two independent​ events, A and​ B, ​P(A)equals . 3 and​P(B)equals . 2 . a. Find ​P(Aintersect ​B). b. Find​ P(A|B). c. Find
Gnoma [55]

Answer:

a) 0.06

b) 0.3

c) 0.44                                        

Step-by-step explanation:

We are given the following in the question:

A and B are two independent events.

P(A) = 0.3

P(B) = 0.2

a) P(A intersect ​B)

P(A\cap B) = P(A)\times P(B) = 0.3\times 0.2 = 0.06  

b) P(A|B)

P(A|B) = \dfrac{P(A\cap B)}{P(B)} = \dfrac{0.06}{0.2} = 0.3

c) P(A union ​B)

P(A\cup B) = P(A) + P(B) - P(A\cap B)\\P(A\cup B) = 0.3 + 0.2 - 0.06 = 0.44

3 0
3 years ago
A scale drawing of a spaceship has a height of 5.5 inches. If the drawing has scale of 1 inch = 34 feet, what is the actual heig
Alja [10]
D. 187 ft is the answer
3 0
3 years ago
5.
AnnZ [28]

Answer:

A. {(-4,-6), (-3,-2), (1,-2), (1,0)}

Step-by-step explanation:

7 0
3 years ago
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Complete the sentence. The midpoint between 2 and 10 is .
ira [324]

Answer:

= 2345<u>6</u><u>7</u><u>8</u><u>9</u><u>1</u><u>0</u>

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5 0
4 years ago
Let C = {n ∈ Z | n = 6r – 5 for some integer r} and D = {m ∈ Z | m = 3s + 1 for some integer s}.
noname [10]

Its is true that C ⊆ D means Every element of C is present in D

According to he question,

Let C = {n ∈ Z | n = 6r – 5 for some integer r}

D = {m ∈ Z | m = 3s + 1 for some integer s}

We have to prove : C ⊆ D

Proof : Let n ∈ C

Then there exists an integer r such that:

n = 6r - 5

Since -5 = -6 + 1

=> n = 6r - 6 + 1

Using distributive property,

=> n = 3(2r - 2) +1

Since , 2 and r are the integers , their product 2r is also an integer and the difference 2r - 2 is also an integer then

Let s = 2r - 2

Then, m = 3r + 1 with r some integer and thus m ∈ D

Since , every element of C is also an element of D

Hence ,  C ⊆ D proved !

Similarly, you have to prove D ⊆ C

To know more about integers here

brainly.com/question/15276410

#SPJ4

7 0
2 years ago
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