Answer:
a) 0.06
b) 0.3
c) 0.44
Step-by-step explanation:
We are given the following in the question:
A and B are two independent events.
P(A) = 0.3
P(B) = 0.2
a) P(A intersect B)
b) P(A|B)

c) P(A union B)

Answer:
A. {(-4,-6), (-3,-2), (1,-2), (1,0)}
Step-by-step explanation:
Answer:
= 2345<u>6</u><u>7</u><u>8</u><u>9</u><u>1</u><u>0</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>=</u><u>6</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>midp</u><u>oint</u>
Its is true that C ⊆ D means Every element of C is present in D
According to he question,
Let C = {n ∈ Z | n = 6r – 5 for some integer r}
D = {m ∈ Z | m = 3s + 1 for some integer s}
We have to prove : C ⊆ D
Proof : Let n ∈ C
Then there exists an integer r such that:
n = 6r - 5
Since -5 = -6 + 1
=> n = 6r - 6 + 1
Using distributive property,
=> n = 3(2r - 2) +1
Since , 2 and r are the integers , their product 2r is also an integer and the difference 2r - 2 is also an integer then
Let s = 2r - 2
Then, m = 3r + 1 with r some integer and thus m ∈ D
Since , every element of C is also an element of D
Hence , C ⊆ D proved !
Similarly, you have to prove D ⊆ C
To know more about integers here
brainly.com/question/15276410
#SPJ4