Find the perimeter And the area of a polygon shown below *in picture*
1 answer:
You might be interested in
Answer:
The drift angle is approximately 7.65° towards the East from the plane's heading
Step-by-step explanation:
The speed of the plane = 350 mph
The direction in which the plane flies N 40° E = 50° counterclockwise from the eastern direction
The speed of the wind = 40 mph
The direction of the wind = S 70° E = 20° clockwise from the eastern direction
The component velocities of the plane are;
= (350 × cos 50)·i + (350 × sin 50)·j
= (40 + cos 20)·i - (40 × sin 40)·j
The resultant speed of the plane = +
= 265.915·i +242.404·j
The direction the plane is heading = tan⁻¹(242.404/265.915) ≈ 42.35°
Therefore, the drift angle = Actual Angle - Direction of the plane = 50 - 42.35 ≈ 7.65° towards the East
<u>→ Chapter : Exponentiation ←</u>
<u><em>≡ We know that:</em></u>
⇔
⇔
<u><em>≡ Solution:</em></u>
⇒
⇒![[4^{(2-5)}].[g^{(3-12)}].[p^{-2}].[m^{5}]](https://tex.z-dn.net/?f=%5B4%5E%7B%282-5%29%7D%5D.%5Bg%5E%7B%283-12%29%7D%5D.%5Bp%5E%7B-2%7D%5D.%5Bm%5E%7B5%7D%5D)
⇒![[4^{-3}].[g^{-9}].[p^{-2}].[m^{5}]](https://tex.z-dn.net/?f=%5B4%5E%7B-3%7D%5D.%5Bg%5E%7B-9%7D%5D.%5Bp%5E%7B-2%7D%5D.%5Bm%5E%7B5%7D%5D)
∴
or 
<u><em>≡ We know that:</em></u>
⇔
⇔
<u><em>≡ Solution:</em></u>
⇒
⇒
⇒
∴