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yanalaym [24]
3 years ago
7

Please guys help thank you so much

Mathematics
1 answer:
Svet_ta [14]3 years ago
6 0
First find a common denominator so you can compare them easier. I chose 12. Multiply the numerator and denominator by the number that makes the denominator 12. 2/3 is multiplied by 4 and 2/4 is multiplied by 3. You are left with 8/12 and 6/12. 8/12 is bigger so it looks like
8/12>6/12
Hope this helps!

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Zina solves a system of linear equations by elimination and finds a solution of (2, 2). One of the equations is a + b = 4. What
kiruha [24]
The answer is -a + b = 0

If she wants to solve <span>a system of linear equations by elimination and if one equation is unknown, one of the solutions in the unknown equation must be negative:
Known equation:       a + b = 4
Unknown equation: -a + b = ?

We know that a = 2 and be = 2, thus: 
</span>Unknown equation: -2 + 2 = 0
The general form of the equation is -a + b = 0

Let's check it out:
Known equation:       a + b = 4
Unknown equation: -a + b = 0
________________________
Add them up:            2b = 4
                                   b = 4/2 = 2

a + b = 4
a = 4 - b
a = 4 - 2
a = 2

So, the second equation is correct.
5 0
3 years ago
Read 2 more answers
Write an equation to find x, then solve for angle measure A. 25 points.
prohojiy [21]

Answer:

Step-by-step explanation:

23). By applying triangle sum theorem in the given triangle,

    (x + 83)° + (x + 48)° + 65° = 180°

    2x + 196 = 180

    2x = -16

    x = -8

    Measure of angle A = x + 48

                                      = -8 + 48

                                      = 40°

     Therefore, Option A is the answer.

24). By triangle sum theorem,

     (3x + 14)° + 90° + (4 + 3x)° = 180°

     6x + 108 = 180

     6x = 72

     x = 12

     Measure of angle A = (4 + 3x)

                                       = 4 + 3(12)

                                       = 40°

     Therefore, Option A is the answer.

8 0
3 years ago
When engaging in weight-control (fitness/fat burning) types of exercise, a person is expected to attain about 60% of their maxim
Nimfa-mama [501]

Answer:

a) <em> standard error of the mean =10.06</em>

<em>b)  The margin of error  = 17.3982</em>

<em>c) 95% of confidence intervals are </em>

<em></em>(89.6018 ,124.3982)<em></em>

<em>d) Lower limit of 95% of confidence interval  = 89.6018</em>

<em>upper limit of 95% of confidence interval  = 124.3982</em>

<em>The Population mean is lies between in these intervals</em>

<u>Step-by-step explanation:</u>

<u><em>Step(i)</em></u><u>:-</u>

Given sample size 'n' = 20

Given sample mean was found to be 107 bpm with a standard deviation of 45 bpm.

<em>Sample mean             </em>x^{-} = 107 bpm<em></em>

<em>Sample standard deviation (S) = 45 bpm</em>

<em>a) standard error of the mean is determined by</em>

<em>     </em>S.E = \frac{S}{\sqrt{n} } = \frac{45}{\sqrt{20} }<em></em>

<em>     S.E = 10.06</em>

<em>b) The margin of error is determined by</em>

<em></em>M.E = \frac{t_{\alpha } X S }{\sqrt{n} }<em></em>

<em>The degrees of freedom  ν   </em>= n-1 =20-1=19<em></em>

<em>   </em>t_{\alpha } = 1.729  

<em></em>M.E = \frac{1.729X 45}{\sqrt{20} }<em></em>

<em></em>M.E = \frac{77.805 }{4.472 } = 17.3982<em></em>

<em>c) 95% of confidence intervals are determined by</em>

<em></em>(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-} + t_{\alpha } \frac{S}{\sqrt{n} } )<em></em>

<em></em>(107 -  1.729\frac{45}{\sqrt{20} } , 107 + 1.729\frac{45}{\sqrt{20} } )<em></em>

<em></em>(107 -  17.3982 } , 107 +17.3982 )<em></em>

<em></em>(89.6018 ,124.3982)<em></em>

<em>d)  </em>

<em>Lower limit of 95% of confidence interval  = 89.6018</em>

<em>upper limit of 95% of confidence interval  = 124.3982</em>

<em>The Population mean is lies between in these intervals</em>

<em></em>

<em></em>

4 0
3 years ago
HELP!! hOW DO YOU FIND FREQUENCY FROM CLASS LIMITS AND CLASS BOUNDARY???? I AM SO CONFUSED.
GaryK [48]
<h3>Answer: See the image attached below for the filled out table</h3>

The third column is optional/extra. It's to show which data values fit in what specific class limit interval.

===================================================

Explanation:

Imagine we had a bunch of cards. Each card will have a number that is from the data set {70, 88, 103, 64, ... etc}

The goal is to sort the cards into 7 boxes. The first box is labeled "60 through 66", the next is "67 through 73", etc.

The first box has 4 cards placed inside it because we have the values {64,65,60,60 } which fit the interval from 60 through 66. Therefore the frequency here is 4.

The next box has the cards labeled {70,69,71,72,70 } inside it. We have 5 cards here, so the frequency is 5.

This pattern is kept up until all of the cards have been sorted into the proper boxes.

What you'll end up with is what you see in the image below. It shows the table of class limits with their corresponding frequencies. I have added a third column to show which values go where, which is optional and likely something you wont put as your answer to the teacher. This third column is just something for you to help keep track of everything.

7 0
3 years ago
Solve these please, thanks in advance!
Llana [10]
C) -64
d)-64
E)64
g)-1
h)1
7 0
3 years ago
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