Your numbers are 11 and 32
We know that:
a + b = 44
and
a = 3b
If we substitute “3b” in for a in the first equation, we get a numerical value for b
3b + b = 44
4b = 44
b = 11
Then we substitute the numerical value of b to solve for a:
a = 3b
a = 3(11) = 33
I reccomend that you add an image or better explain what you want us to do.
Answer:
The center is (5, -2) and the radius is 9/2
Step-by-step explanation:
The equation of a circle can be written by
(x-h) ^2 + (y-k)^2 = r^2
where (h,k) is the center and r is the radius
(x-5)^{2}+(y+2)^{2} = 81/4
( (x-5)^{2}+(y- -2)^{2} = (9/2)^2
The center is (5, -2) and the radius is 9/2
-2. Because on the number line it goes -3 -2 -1 0 1 2 3 so if you count backwards from 2 it is -2
Add like terms and then simplify
