Answer:
x=27
Step-by-step explanation:
180-2x-40+180-3x+180-x-50+180-4x = 360
360-2x-40-3x+360-x-50-4x= 360
360-10x-90= 0
10x= 270
x= 27
<span>Number of times that a spin comes up 1 divided by the total number of spins.
P(1) = 8/21</span><span>
</span>
Answer:
Answer A: 300 n - 2200
Step-by-step explanation:
The profit function will be the income minus the cost of maintaining the boathouse.
The income comes from the number of boats that it docks (n) , times the monthly fee that each boat pays ($850), That is:
Income = 850 n
Now the monthly cost to operate the boathouse is the fix $2200 cost plus $550 per boat. That is:
2200 + 550 n
Now, the difference "Income - Cost" that defines the profit function becomes:
850 n - {2200 + 550 n} = 850 n - 550 n - 2200 = 300 n - 2200
Answer:
6/16, perhaps?
Good luck! And if you could, please mark me brainliest. :)
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Answer:
- f(x) = -0.15x^2 +19.8x -11 . . . profit function
- $642.40 maximum daily profit
- 66 gallons sold
- $10.90 per gallon
Step-by-step explanation:
<u>Given</u>:
daily cost function c(x) = x +11
price-demand function p(x) = -0.15x +20.8
<u>Find</u>:
daily profit function
maximum daily profit
quantity sold for maximum profit
price for maximum profit
<u>Solution</u>:
The revenue is the product of price and demand:
x·p(x) = -0.15x^2 +20.8x
The profit is the difference between revenue and cost:
f(x) = x·p(x) -c(x) = -0.15x^2 +20.8x -x -11
f(x) = -0.15x^2 +19.8x -11 . . . . . daily profit function
__
The maximum profit will be had a the vertex of the curve, found where ...
x = -(19.8)/(2(-0.15)) = 66
f(66) = (-0.15·66 +19.8)66 -11 = 9.9·66 -11 = 642.40
The maximum profit is $642.40, when 66 gallons of ice cream are sold.
__
The price that will result in demand of 66 gallons of ice cream is ...
p(66) = -0.15(66) +20.8 = 10.9
The price to charge per gallon to maximize profit is $10.90.