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2 years ago

How many of the first 999 Fibonacci numbers are odd?

1 answer:

7 0

Every 3rd number is even with 2 odd numbers in between successive even numbers.

999/3 = 333 x 2 = 666.

If you need any more help, tag me :)

Thank you,
Darian

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Twenty-four minus three times an integer,x, is less than x minus four

Inga [223]

The answer is:
24 - 3x < x - 4

8 0

2 years ago

a school cafeteria is considering new menu options. the manager puts a comment box jn the cafeteria where students can anonymous

viktelen [127]

Answer:

No, it is not a representative sample

Step-by-step explanation:

The sampling technique used above is more of a random sampling than a representative sampling. Reason is that;

A representative sample is referred to as a group or set selected from a larger population that satisfactorily represent the population in study in accordance to whatever criteria is under study.

The criteria could be age, sex, class, etc.

Another reason why it can't be considered as a representative sample is that, using representative sampling makes sure that all relevant types of people are included in your sample and that the right mix of people are interviewed.

In the question above, anybody can submit his or choice and number of submissions is not limited.

8 0

2 years ago

6. (07.02 MC)

Alexus [3.1K]

Answer:

x = 28.07°

Step-by-step explanation:

Recall: SOH CAH TOA

Reference angle given = x°

Opposite = 8

Hypotenuse = 17

Apply SOH:

$Sin x = \frac{Opp}{Hyp}$

Substitute

$Sin x = \frac{8}{17}$

$x = sin^{-1}(\frac{8}{17})$

x = 28.07° (nearest hundredth)

5 0

2 years ago

A physicist examines 25 water samples for nitrate concentration. The mean nitrate concentration for the sample data is 0.165 cc/

xz_007 [3.2K]

Answer:

The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).

Critical value t=1.318

Step-by-step explanation:

We have to calculate a 80% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=0.165.

The sample size is N=25.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.078}{\sqrt{25}}=\dfrac{0.078}{5}=0.016$

The degrees of freedom for this sample size are:

$df=n-1=25-1=24$

The t-value for a 80% confidence interval and 24 degrees of freedom is t=1.318.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=1.318 \cdot 0.016=0.021$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 0.165-0.021=0.144\\\\UL=M+t \cdot s_M = 0.165+0.021=0.186$

The 80% confidence interval for the population mean nitrate concentration is (0.144, 0.186).

6 0

3 years ago

Please help asap 30 pts

Sergio [31]

$4w-2(1-w)=-38\qquad|\text{use distributive property}\\\\4w+(-2)(1)+(-2)(-w)=-38\\\\4w-2+2w=-38\qquad|\text{add 2 to both sides}\\\\4w+2w=-36\\\\6w=-36\qquad|\text{divide both sides by 6}\\\\\boxed{w=-6}$

<h3>Answer: d. w = -6</h3>

4 0

2 years ago