Answer: I think you somehow managed to try to make an answer and then accidentally clicked "add a question" and then just so happened to not realize, so you made your answer as a question...
Step-by-step explanation:
Kidding, but I'm not sure what this is supposed to be answering... There is not much context given lol.
positive number times negative number is negative number "(+)(-) = (-)".

we change the mixed numbers to the improper fractions

What are the possible answers ?

Here, we want to find the diagonal of the given solid
To do this, we need the appropriate triangle
Firstly, we need the diagonal of the base
To get this, we use Pythagoras' theorem for the base
The other measures are 6 mm and 8 mm
According ro Pythagoras' ; the square of the hypotenuse equals the sum of the squares of the two other sides
Let us have the diagonal as l
Mathematically;
![\begin{gathered} l^2=6^2+8^2 \\ l^2\text{ = 36 + 64} \\ l^2\text{ =100} \\ l\text{ = }\sqrt[]{100} \\ l\text{ = 10 mm} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20l%5E2%3D6%5E2%2B8%5E2%20%5C%5C%20l%5E2%5Ctext%7B%20%3D%2036%20%2B%2064%7D%20%5C%5C%20l%5E2%5Ctext%7B%20%3D100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%2010%20mm%7D%20%5Cend%7Bgathered%7D)
Now, to get the diagonal, we use the triangle with height 5 mm and the base being the hypotenuse we calculated above
Thus, we calculate this using the Pytthagoras' theorem as follows;
<h3>
You need to add 4 to both sides</h3>
The x term has a coefficient of 4. Take half of this to get 2, then square it to get 4. This is the value we add to both sides to get x^2+4x+4 = 5. Note how x^2+4x+4 factors into (x+2)^2
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Another example: Let's say we started with x^2+6x = 1. To complete the square, we need to add 9 to both sides. I start with 6 (the x coefficient) and cut that in half to get 3, then I squared that to get 9. So we add 9 to both sides getting x^2+6x+9 = 10 which becomes (x+3)^2 = 10