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earnstyle [38]
3 years ago
8

To know the answer to this

Mathematics
1 answer:
marin [14]3 years ago
8 0

Answer:

3.2

Step-by-step explanation:

4.7 - 1.5 = 3.2 that's an A

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What is the total area of the shaded triangles?
frozen [14]
Check the picture below.

\bf \textit{area of an equilateral triangle}\\\\
A=\cfrac{s^2\sqrt{3}}{4}~~
\begin{cases}
s=length~of\\
\qquad a~side\\
------\\
s=\frac{s}{3}
\end{cases}\implies A=\cfrac{\left( \frac{s}{3} \right)^2\sqrt{3}}{4}
\\\\\\
A=\cfrac{\frac{s^2\sqrt{3}}{3^2}}{4}\implies A=\cfrac{s^2\sqrt{3}}{4\cdot 3^2}\implies A=\cfrac{s^2\sqrt{3}}{36}
\\\\\\
\textit{and since there are 3 triangles shaded with that area}
\\\\\\
\textit{shaded area}\implies 3\left( \cfrac{s^2\sqrt{3}}{36} \right)\implies \cfrac{s^2\sqrt{3}}{12}

6 0
4 years ago
Direction: Answer the following problem sets. Please include what is the given, asked, formula, solution and final answer with u
olga2289 [7]

Answer:

7.5s

1.6666 repeating or 1.67 m/s²

Step-by-step explanation:

the equation you have to use is Vfinal=Vstart+acceleration•time

(I'm gonna simplify to Vf=Vs+at)

so you gotta rework it for the two equations

for the first equation you need time so take Vf=Vs+at and subtract Vs on both sides to get Vf–Vs=at

then divide acceleration on both sides to get t=(Vf–Vs)/a

for the second problem equation need the equation a=(Vf–Vs)/t (just divide time on both sides instead of acceleration)

so you the plug in

(I don't put the units in to the problem unless needed)

1. t=(Vf–Vs)/a to t=(0–30)/-4.0

t= -30/-4.0

t=7.5 seconds

2. a=(Vf–Vs)/t to a=(10–0)/6.0

a= 10/6.0

a= 1.67m/s²

(I'm assuming the that for number two they started at rest so it would be 0m/s for velocity start)

8 0
3 years ago
Fine the slope of the line graphed ?
strojnjashka [21]

Answer:

C. 2/5

Hope this helps!!!!!!!!

4 0
4 years ago
Brainliest for answer
Arlecino [84]

4/15 !! hope it helps loll

3 0
3 years ago
Do we really have to pass the acp exam to pass the semester class in texas?
lawyer [7]
Yes I believes so I hope I helped ya
4 0
3 years ago
Read 2 more answers
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