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JulsSmile [24]
3 years ago
8

First.

Mathematics
2 answers:
klio [65]3 years ago
5 0

Answer:

Step-by-step explanation:

addition and subtraction i think i will turn my test in and edit

velikii [3]3 years ago
3 0

Answer:o

Step-by-step explanation:

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The table shows the number of hours spent practicing singing each week in three samples of 10 randomly selected chorus members.
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B they are close together

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Adam’s bank account has a balance of $1213.69 before he starts spending money. He makes the following transactions:
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The absolute value of—
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A

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4 years ago
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our friend is graphing the point (1, 7). Her first step is to start at the origin and go right 7 spaces. Is her method correct?
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4 years ago
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Mr. Richard's science class is conducting a variety of experiments with projectiles and falling objects. Two groups of students
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<span>In general, the height of a projectile is given by

</span>h= -\frac 1 2 g t^2 + v t + h_0
<span>
where </span>h is the height at time t of a projectile shot upward at velocity v from initial height h_0<span>.

The acceleration of gravity </span>g= 9.8 \textrm {m/s}^2 \textrm{ or } g=32\textrm{ feet/s}^2.<span>  We give it a negative sign in the equation because it pulls down.

Let's apply it to each group.

Group A launches a tennis ball straight up with an initial velocity of 19 meters per second.

We have MKS units, positive (upward) velocity and an initial height of 0.

</span>h= -\frac 1 2(9.8) t^2 + (19) t + 0 = -4.9t^2 + 19t
<span>
Group B launches a tennis ball straight up with an initial velocity of 50 feet per second.    Not metric, velocity +50, initial height zero.

</span>h= -16t^2 + 50t
<span>
Group C drops a tennis ball from a height of 19 meters.

MKS, initial height 19, initial velocity zero.

</span>h= -\frac 1 2 g t^2 + v t + h_0 = -4.9 t^2 + 19
<span>
Group D drops a tennis ball from a height of 50 feet. 

</span>h= -16 t^2 + 50
<span>


</span>
6 0
4 years ago
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