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GalinKa [24]
3 years ago
13

Find m∠3 if m∠5=130 and m∠4 =70

Mathematics
2 answers:
kari74 [83]3 years ago
6 0

Answer:  The required measure of angle 3 is 60°.

Step-by-step explanation:  We are given to find the measure of angle 3 from the figure if

m∠5 = 130° and m∠4 = 70°.

Let the measure of angle 3 be x°.

From the figure, we note that

angle 5 is an exterior angle and angles 3 and 4 are two remote interior angles of the triangle.

We know that

the measure of an exterior angle to a triangle is equal to the sum of the measures of two remote interior angles.

So, we get

m\angle 5=m\angle 3+m\angle 4\\\\\Rightarrow 130^\circ=x+70^\circ\\\\\Rightarrow x=130^\circ-70^\circ\\\\\Rightarrow x=60^\circ.

Thus, the required measure of angle 3 is 60°.

arlik [135]3 years ago
3 0
M∠5=130 <span>and m∠4 =70
</span><span>so
m<2 = 180 - m<5 
m<2 = 180 - 130
m<2 = 50

m<3 = 180 - (m<2  + m<4)
</span>m<3 = 180 - (50+70)
m<3 = 180 - 120
m<3 = 60
<span>



</span>
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erik [133]

Answer:

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

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Step-by-step explanation:

we have

y=-x^{2} +2x+10 ----> equation A

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Solve the system by substitution

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The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

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in this problem we have

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x=\frac{-1+\sqrt{33}} {-2}  -----> x=\frac{1-\sqrt{33}} {2}  

x=\frac{-1-\sqrt{33}} {-2}  -----> x=\frac{1+\sqrt{33}} {2}  

<em>Find the values of y</em>

For x=\frac{1-\sqrt{33}} {2}  

y=x+2

y=\frac{1-\sqrt{33}} {2}+2  ---->y=\frac{5-\sqrt{33}} {2}  

For x=\frac{1+\sqrt{33}} {2}  

y=x+2

y=\frac{1+\sqrt{33}} {2}+2  ---->y=\frac{5+\sqrt{33}} {2}  

therefore

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(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

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