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GalinKa [24]
3 years ago
13

Find m∠3 if m∠5=130 and m∠4 =70

Mathematics
2 answers:
kari74 [83]3 years ago
6 0

Answer:  The required measure of angle 3 is 60°.

Step-by-step explanation:  We are given to find the measure of angle 3 from the figure if

m∠5 = 130° and m∠4 = 70°.

Let the measure of angle 3 be x°.

From the figure, we note that

angle 5 is an exterior angle and angles 3 and 4 are two remote interior angles of the triangle.

We know that

the measure of an exterior angle to a triangle is equal to the sum of the measures of two remote interior angles.

So, we get

m\angle 5=m\angle 3+m\angle 4\\\\\Rightarrow 130^\circ=x+70^\circ\\\\\Rightarrow x=130^\circ-70^\circ\\\\\Rightarrow x=60^\circ.

Thus, the required measure of angle 3 is 60°.

arlik [135]3 years ago
3 0
M∠5=130 <span>and m∠4 =70
</span><span>so
m<2 = 180 - m<5 
m<2 = 180 - 130
m<2 = 50

m<3 = 180 - (m<2  + m<4)
</span>m<3 = 180 - (50+70)
m<3 = 180 - 120
m<3 = 60
<span>



</span>
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There were 2747 yes votes.

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This question can be solved using proportions.

The ratio of yes votes to no votes was 5 to 3 .

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Read 2 more answers
PLEASE HELP ME!!!!!!
Nata [24]

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Answer:

  vertex: (2, -3.2)

  axis of symmetry: x = 2

  zeros: x=0, x=4

  formula for axis of symmetry:

  • x = <x-coordinate of vertex>
  • x = -b/(2a) . . . . . . . where the quadratic is ax^2 +bx +c
  • x = average of zeros, (z1 +z2)/2

Step-by-step explanation:

a) The vertex x-coordinate is halfway between the zeros, so is x = (0+4)/2 = 2. It is where the graph has a turning point.

The vertex y-coordinate is the low point of this graph. It is not on a grid line, so we can only guess at its value. I choose to call it -3.2.

The vertex is (2, -3.2).

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b) The axis of symmetry is the vertical line through the vertex. The constant in its equation is the x-coordinate of the vertex:

  x = 2

__

c) The zeros of the function are where the function crosses the x-axis. These are marked on the graph with red dots. The zeros are x=0 and x=4.

__

d) When the quadratic is written in standard form, ax^2 +bx +c, the equation of the axis of symmetry is ...

  x = -b/(2a) . . . . . perhaps this is the formula you're being asked for (?)

When there is no equation, the axis of symmetry can be found from the graph a couple of ways. One is to identify the x-coordinate of the vertex.

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Another is to average the zeros, since they are symmetrical about the axis of symmetry.

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If the quadratic is written in vertex form, the vertex coordinate is the constant in the equation for the axis of symmetry.

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