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Papessa [141]
3 years ago
8

A class is divided into 4 groups. A bag contains pieces of paper that are red, blue, green, and yellow. For every blue- or green

-colored piece of paper, there are 2 red- and 2 yellow-colored pieces of paper. The students are asked to pick a piece of paper to be put into a particular colored group. What is the probability that the first student will randomly pick a red-colored piece of paper or a blue-colored piece of paper? What additional information would be required to solve the problem?
Mathematics
1 answer:
DIA [1.3K]3 years ago
7 0
1.) The red piece of paper will be higher than the blue one. 
Red: 2:1
Blue: 1:2 
2.) How much papers are there. 


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I am Lyosha [343]

Answer:

Part 9) x=5  

Part 10) x=-9  

Step-by-step explanation:

we know that

The <u><em>Midpoint Theorem</em></u> states that: The segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side

Part 9) we know that

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Applying the Midpoint Theorem

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we have

RQ=2x-3\\WY=x+9

substitute

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Part 10) we know that

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Point C is the midpoint segment RS (CS=CR)

Applying the Midpoint Theorem

BC is parallel to TR

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BC=\frac{1}{2}TR  

we have

BC=x+19\\TR=x+29

substitute

x+19=\frac{1}{2}(x+29)  

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5 0
3 years ago
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irga5000 [103]

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3 0
3 years ago
Read 2 more answers
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gulaghasi [49]

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n = 3/4

Now you have a value for n, replace n and solve for the length:

7n = 7(3/4) = 21/4 = 5 1/4

Each side is 5 1/4

7 0
3 years ago
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