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eimsori [14]
3 years ago
15

To keep you from inadvertently moving controls as you work in the IDE, click the form or control, then click the _________ optio

n in the Format menu. (or you can choose this option from the menu that appears when you right-click on the form in the Designer) Group of answer choices Hold Freeze Controls Protect Lock Controls
Computers and Technology
1 answer:
Alenkinab [10]3 years ago
4 0

Answer:

Lock controls

Explanation:

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You just received a message from the internet which was encrypted with asymmetric encryption. what do you need to do to read the
Bezzdna [24]
Assuming the data was encrypted with YOUR public key, you'll need YOUR private key to decrypt it. That's answer e.

a and b are not solutions by themselves, of course you need to use the decryption algorithm, but a key goes with it.

c would be about symmetric encryption, but this is asymmetric, so different keys are used for encryption and decryption

d is possible, but it would mean anyone can decrypt it (after all the key is public), so then there's no point in encrypting it in the first place.

So e is the only logical answer.
5 0
3 years ago
Write a statement to create a Google Guava Multimap instance which contains student ids as keys and the associated values are st
Sergeu [11.5K]

Answer: provided in the explanation section

Explanation:

Note: take note for indentation so as to prevent error.

So we import com.google.common.collect.Multimap;

import java.util.Collection;

import java.util.Map;

class Main {

   public static void main(String[] args) {

       // key as studentId and List of Profile as value.

       Multimap<String,Profile> multimap = ArrayListMultimap.create();

       multimap.put("id1", new ExamProfile("examStudentId1"));

       multimap.put("id1", new ELearningProfile("userId1"));

       multimap.put("id2", new ExamProfile("examStudentId2"));

       multimap.put("id2", new ELearningProfile("userId2"));

       // print the data now.

       for (Map.Entry<String, Collection<Profile>> entry : multimap.entrySet()) {

           String key = entry.getKey();

           Collection<String> value =  multimap.get(key);

           System.out.println(key + ":" + value);

       }

   }

}

// assuming String as the studentId.

// assuming Profile as the interface. And Profile can multiple implementations that would be

// specific to student.

interface Profile {

}

class ExamProfile implements Profile {

   private String examStudentId;

   public ExamProfile(String examStudentId) {

       this.examStudentId = examStudentId;

   }

}

class ELearningProfile implements Profile {

   private String userId;

   public ELearningProfile(String userId) {

       this.userId = userId;

   }

}

This code is able to iterate through all entries in the Google Guava multimap and display all the students name in the associated students profile.

8 0
3 years ago
This is your code.
lubasha [3.4K]

Answer:

35

Explanation:

We will be going inside B array, because he was in second place in array E,and will be the first element of array B, so it's 35

E can be understanded as:

E=[[21, 'dog', 'red'],[35, 'cat', 'blue'],[12, 'fish', 'green']], so, you can see array E as array of arrays or so-called two-dimensional array

6 0
2 years ago
In a word processing program, under which tab or menu option can you adjust the picture brightness?
Otrada [13]
B. format because changing the brightness of the photo is changing its default format
5 0
3 years ago
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Plz help meeeeee QUICKLY!!! WORTH 15 POINTS!
Lady bird [3.3K]

Answer:

Im pretty sure Domain name system but dont trust me

Explanation:

8 0
3 years ago
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