Answer:
0.18
Step-by-step explanation:
C is a subpath of A,
first P(A) = 0.6 since the line leading to A says .6
the probability of choosing C is 0.3, but first we have to assume A is chosen. The true probability is 0.3 * 0.6 = 0.18
Answer:
Our answer is 0.8172
Step-by-step explanation:
P(doubles on a single roll of pair of dice) =(6/36) =1/6
therefore P(in 3 rolls of pair of dice at least one doubles)=1-P(none of roll shows a double)
=1-(1-1/6)3 =91/216
for 12 players this follows binomial distribution with parameter n=12 and p=91/216
probability that at least 4 of the players will get “doubles” at least once =P(X>=4)
=1-(P(X<=3)
=1-((₁₂ C0)×(91/216)⁰(125/216)¹²+(₁₂ C1)×(91/216)¹(125/216)¹¹+(₁₂ C2)×(91/216)²(125/216)¹⁰+(₁₂ C3)×(91/216)³(125/216)⁹)
=1-0.1828
=0.8172
Answer:
I am pretty sure the answer is 30 blocks :)
4 + 11 + 6 + 9 = 30 blocks
Answer:
3(p+4m) + 8
Step-by-step explanation:
Factor out a 3 for the first two terms, 3(p+4m) and add 8 like usual