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kompoz [17]
3 years ago
15

What single transformation maps ∆ABC onto ∆A'B'C'? A. rotation 90° clockwise about the origin B. rotation 90° counterclockwise a

bout the origin C. reflection across the x-axis D. reflection across the line y = x

Mathematics
2 answers:
Klio2033 [76]3 years ago
8 0

Answer:

B. rotation 90° counterclockwise about the origin.

Step-by-step explanation:

Transformation is the process by which the size or orientation of a given figure is altered without any effect on its shape. Examples are; rotation, reflection, translation and dilation.

Rotation is the process of turning a figure about a reference point called the origin. While reflection is turning a figure about a line to produce its image.

In the given question, ∆ABC is  mapped onto ∆A'B'C' by rotating it at 90° counterclockwise about the origin.

Vera_Pavlovna [14]3 years ago
5 0

Answer:

B. rotation 90° counterclockwise about the origin.

Step-by-step explanation:

Transformation is the process by which the size or orientation of a given figure is altered without any effect on its shape. Examples are; rotation, reflection, translation and dilation.

Rotation is the process of turning a figure about a reference point called the origin. While reflection is turning a figure about a line to produce its image.

In the given question, ∆ABC is  mapped onto ∆A'B'C' by rotating it at 90° counterclockwise about the origin.

Step-by-step explanation:

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The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of
kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

A=\frac{\sqrt{3} }{4} a^{2}

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}

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Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

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\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )

\frac{A_{1}}{A_{2}} = 2.25

<u>The area of ΔABC is </u><u>2.25x</u><u> greater than the area of ΔDEF.</u>

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