Solve the equation for x<br> (×-5)=10 where y =3<br> __

The volume of a sphere is a function of its radius, V=4/3(pie)(r^3). Evaluate the function for the volume of a volleyball with

Travka [436]

Volume of a volleyball (a sphere) = 4/3πr³
= 4/3π(11.4)³
= 1975.392π
= 6210 cm³ (to 3 significant figures)

The volume of a volleyball with a radius of 11.4 cm will be 6210 cm³.

5 0

3 years ago

Look at picture (15 point)

NNADVOKAT [17]

Answer:

Option C is the correct option

Step by step explanation

$\sqrt{ \frac{22 {x}^{6} }{11 {x}^{4} } }$

Reduce the fraction with 11

$\sqrt{ \frac{2 {x}^{6} }{ {x}^{4} } }$

Simplify the expression

$\sqrt{2 {x}^{6 - 4} }$

$\sqrt{2 \: {x}^{2} }$

Simplify the radical expression

$x \sqrt{2}$

Hope this helps...

Good luck on your assignment..

3 0

3 years ago

20 square root of 270 /4 square root of 3

OleMash [197]

Answer:

<u>The most simplified form is 15√10</u>

Step-by-step explanation:

1. Let's simplify the expression:

20√270 ÷ 4√3

20√9 * 30/ 4√3 (√270 = √9 * 30)

60 √30/ 4√3

(60 √3 * √10) / 4√3 (√30 = √3 * √10)

60/4 √10 ( We cancel √3 in the numerator and in the denominator)

15√10

<u>The most simplified form is 15√10</u>

6 0

3 years ago

PLEASE HELP ASAP THANKS IN ADVANCE

chubhunter [2.5K]

Answer:

the answer to the question is "C"

7 0

3 years ago

The Scottsdale fire department aims to respond to fire calls in 4 minutes or less, on average. Response times are normally distr

IgorC [24]

<h2><u>Answer with explanation</u>:</h2>

Let $\mu$ be the population mean.

As per given , we have

$H_0:\mu \leq4\\\\ H_a: \mu >4$

Since the alternative hypothesis is right-tailed , so the test is a right-tailed test.

Also, population standard deviation is given $\sigma=1$ , so we perform one-tailed z-test.

Test statistic : $z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

, where $\mu$ = Population mean

$\sigma$ = Population standard deviation

n= sample size

$\overline{x}$ = Sample mean

For n= 18 , $\overline{x}=4.50$ , $\sigma=1$ , $\mu =4$ , we have

$z=\dfrac{4.5-4}{\dfrac{1}{\sqrt{18}}}\approx2.12$

P-value (for right tailed test): P(z>2.12) = 1-P(z≤ 2.12) [∵ P(Z>z)=1-P(Z≤z)]\

=1- 0.0340=0.9660

Decision : Since P-value(0.9660) > Significance level (0.01), it means we are failed to reject the null hypothesis.

[We reject null hypothesis if p-value is larger than the significance level . ]

Conclusion : We do not have sufficient evidence to show that the goal is not being met at α = .01 .

3 0

3 years ago

Solve the equation for x (×-5)=10 where y =3 ___ y