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3 years ago

Solve the equation for x (×-5)=10 where y =3 ___ y

Mathematics

1 answer:

seraphim [82]3 years ago

7 0

X is going to be equal to 15

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3 years ago

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Use the power-reducing formulas to rewrite the expression as an equivalent expression that does not contain powers of trigonome

ratelena [41]

Answer:

$x = 0.175\cdot (1-\cos 4\cdot \theta)$

Step-by-step explanation:

Let use the following trigonometric identities:

$\sin^{2}\theta = \frac{1-\cos 2\cdot \theta}{2} \\\cos^{2}\theta = \frac{1+\cos 2\cdot \theta}{2}$

Then, the equation is simplified by substituting its components:

$x = 1.40\cdot \left(\frac{1-\cos 2\cdot \theta}{2} \right)\cdot \left(\frac{1+\cos 2\cdot \theta}{2} \right)$

$x = 0.35\cdot (1-\cos^{2}2\cdot \theta)$

$x = 0.35\cdot \sin^{2}2\cdot \theta$

$x = 0.35\cdot \left(\frac{1-\cos 4\cdot \theta}{2} \right)$

$x = 0.175\cdot (1-\cos 4\cdot \theta)$

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4 years ago

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The graph shows the speed of a ball in free fall for 10 seconds. Which is the constant of proportionality shown in the graph? It

Tresset [83]

Answer:A

Step-by-step explanation:

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3 years ago

Express each of these numbers as a product of two fractions: 1

Murrr4er [49]

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4 years ago

You own a motel and have a pricing structure that encourages rentals of rooms in groups.

zheka24 [161]

Answer:

$41

Step-by-step explanation:

One room rents for $68,
Two rooms for $65 each,
In general, the group rate per room is found by taking $3 off the base of $68 for each extra room.

So,

$a_1=\$68\\ \\a_2=\$65\\ \\a_3=\$62\\ \\...$

where $a_n$ is the rate per nth room rented.

This is an arithmetic sequence, so

$a_n=a_1+(n-1)\cdot d$

In your case,

$a_1=68\\ \\n=10\\ \\d=-3$

Hence

$a_{10}=68+(10-1)\cdot (-3)=68-9\cdot 3=68-27=41$

This means if a group rents 10 rooms, the charge per room is $41.

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3 years ago