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3 years ago

If R represents the third vertex in the triangle and R is located in the third quadrant, what is the length of PR?

Mathematics

2 answers:

lisov135 [29]3 years ago

7 0

It should be 5. I just took it on Edgenuity....

horrorfan [7]3 years ago

4 0

Answer:

its 5

Step-by-step explanation:

i took the test. ✨✨✨

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ABC is the image of ABC under a translation

morpeh [17]

The translation is (x-8,y+5). To get from A to A’ you go left (x-axis) 8 times and up (y-axis) 5 times.

8 0

3 years ago

Slope: 3/4, y-intercept: -1

Amiraneli [1.4K]

Answer:

y = 3/4 x -1

Step-by-step explanation:

The equation for a line with the slope and the intercept is y = mx+b where m is the slope and b is the y intercept

y = 3/4 x -1

5 0

3 years ago

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Solve for x.

Ivahew [28]

ANSWER

$x=\frac{2-\sqrt{10}} {3}$

or

$x=\frac{\sqrt{10}+2} {3}$

We have

$3x^2-4x-2=0$

Since we cannot factor easily, we complete the square.

Adding 2 to both sides give,

$3x^2-4x=2$

Dividing through by 3 gives

$x^2-\frac{4}{3}x= \frac{2}{3}$

Adding $(-\frac{2}{3})^2$ to both sides gives

$x^2-\frac{4}{3}x+(-\frac{2}{3})^2= \frac{2}{3}+(-\frac{2}{3})^2$

The expression on the Left Hand side is a perfect square.

$(x-\frac{2}{3})^2= \frac{2}{3}+\frac{4}{9}$

$\Rightarrow (x-\frac{2}{3})^2= \frac{10}{9}$

$\Rightarrow (x-\frac{2}{3})=\pm \sqrt{\frac{10}{9}}$

$\Rightarrow (x)=\frac{2}{3} \pm {\frac{\sqrt{10}}{3}$

Splitting the plus or minus sign gives

$x=\frac{2- \sqrt{10}} {3}$

or

$x=\frac{\sqrt{10}+2} {3}$

3 0

3 years ago

Read 2 more answers

PLEASE HELP MEEE I CANT DII

irina1246 [14]

Answer:

12 pieces of sausage can be cut from the 8 inch sausage if each piece is 2/3 of an inch.

Step-by-step explanation:

2/3 = 0.66

8 x 0.66 = 12.12

Round down to 12.

I hope this helped you! If it did, please consider rating my answer, pressing thanks, and marking as Brainliest. Have a great day!

7 0

2 years ago

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Which sequence of a transformation will result in an image that maps onto itself? A) rotate 180 degrees counterclockwise and the

Firdavs [7]

The <em>correct answer</em> is:

D) reflect over the y axis and then reflect again over the y axis.

Explanation:

Logically, if we reflect a figure across the y-axis and then reflect across the y-axis again, we have undone what we originally did, and the figure is back in its original position.

Algebraically, reflecting across the y-axis maps every point (x, y) to (-x, y). Reflecting this point across the y-axis maps (-x, y) to (x, y); this is our original point.

6 0

3 years ago

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