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pentagon [3]
3 years ago
8

Solve 3x2 + 6x = 8.

Mathematics
2 answers:
-Dominant- [34]3 years ago
8 0

Answer:

The quantity of negative 1 plus or minus square root 33 all over 3

Step-by-step explanation:

3x2+6x=8

3x^2+6x-8=0

Quadratic formula

x=-b +or-√b^2-4ac/2a

a=3

b=6

c=-8

x=-b +or-√b^2-4ac/2a

=-6 +or- √(6)^2 - 4*3*-8/2*3

=-6 +or- √36-(-96)/6

=-6 +or-√36+96/132

=-6 +or- √132/6

=-6 +or- 2√33/6

=-6/6 +or- 2√33/6

= -1 +or- √33/3

The quantity of negative 1 plus or minus square root 33 all over 3

Katyanochek1 [597]3 years ago
6 0

Answer: C

quantity of -3 +/- square root 33 all over 3

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Calculate the perimeter of the following shape.<br>6cm<br>y=<br>10 cm<br>12 cm<br>5 cm​
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Answer:

The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides.

10 cm + 12 cm + 5 cm + 6 cm

= 33 cm

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2x-(10+4x)=3x-7 what is the answer
ZanzabumX [31]
X=-3/5

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3 years ago
If you help will make you brainlest
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see below

Step by step explanation

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2 years ago
In ΔABC, AD and BE are the angle bisectors of ∠A and ∠B and DE║ AB. Find the measures of the angles of ΔABC, if m∠ADE: m∠ADB = 2
drek231 [11]

Answer:   ∠A=48°,∠B=48°,∠C=84°.


Step by-step explanation:

Given:  AD and BE are the angle bisectors  of ∠A and ∠B

i.e ∠6=∠7    ( ∵ Angles formed after  AD bisected ∠A)

∠4=∠5       ( ∵ Angles formed after  BE bisected ∠B)

Also,  DE║AB

⇒ ∠2=∠7   (∵ Alternate interior angles)

   ∠3=∠6   (∵ Alternate interior angles)

And ∠ADE : ∠ADB =∠2:∠3= 2:9 =2x : 9x     ..(1)

To Find:  ∠A,∠B,∠C.

Solution:  ∠2=∠7 (∵ Given)    ...(2)

∠2=∠4  (∵ angles on the same segment)    ...(3)

∠4=∠5 =∠B/2 (∵ Given)    ...(4)

∴ In Δ ABD

∠3+∠4+∠5+∠7 = 180 (∵ Sum of interior angles of a triangle)

From equation 2,3,4,5, Put values

9x+2x+2x+2x =180°

⇒15x = 180°

⇒x=12°

Putting values in equation (4) ⇒ ∠ B =2*(2*12) = 48°

Also, <u>∠B=∠A=48°</u>

Now,in Δ ABC

∠C+∠B+∠A= 180°

⇒48°+48°+∠C= 180°

<u><em>⇒∠C=84°</em></u>

6 0
3 years ago
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