Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
Hey there!
Let's solve the equation.
20=6x+14
Subtract 14 from both sides.
6=6x
Divide 6 on both sides.
x=1
This is false.
I hope this helps!
~kaikers
Hey ! I know for sure A is one of the correct answers i’m working on the rest now
Answer:D
Step-by-step explanation:
