Answer:
(The sum) is the combined flow of return flow and DPS.
Answer:
The Bulk density = 1.3 g/cm³
the porosity of the sample is 132 cm³
Explanation:
Given:
Volume of cylinder = 260 cm³
Mass of container and the soil = 403 g
Mass of the empty container = 65 g
Thus,
The mass of the soil is = 403 - 65 = 338 g
Now,
The Bulk density = 
or
The Bulk density = 
or
The Bulk density = 1.3 g/cm³
also,
average particle density for mineral soil is usually given as 2.65 g/cm³
i.e the air present in the given soil sample has reduced its density from 2.65 g/cm³ to 1.3 g/cm³
The mass of the whole sample = Volume × Density
= 260 × 2.65
= 689 gm
but,
The actual mass of the dry sample = 338 g
thus,
Mass of air in the sample = 689 - 338 = 351 g
Therefore,
the volume of 351 g soil = 
= 
= 132.45 cm³
so the porosity of the sample is 132 cm³
Answer:
The option C would be a true statement
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