Hi there!

The two trapezoids are similar, so we can determine a common scale factor:
OL/UR = NM/TS
9/3 = 6/2
3 = 3
Trapezoid ONML is 3x larger than UTSR, so:
RS = 4, LM = y
3RS = LM
3 · 4 = y = 12.
Find x using the same method:
3UT = ON
3(2x+1) = 4x + 9
6x + 3 = 4x + 9
2x = 6
x = 3.
Answer:
14
Step-by-step explanation:
70
1 * 70
5 * 14
7 * 10
42
1 * 42
3 * 14
7 * 6
28
1 * 28
2 * 14
7 * 4
pick the largest factor from 70 and check it they also work with the other two. 14 is the GCF.
Answer:
The experimental probability is 1/6
Step-by-step explanation:
WIN = 8/48
= 1/6 or 0.1667 = 16.67% chance of winning
LOSE = 40/48
= 5/6 or 0.8333 = 83.33% chance of losing.
I hope this helps. ;)
Answer:
Shown
Step-by-step explanation:
Given that twelve basketball players, whose uniforms are numbered 1 through 12, stand around the center ring on the court in an arbitrary arrangement.
Let us consider consecutive numbers in this set.

After this we find the totals are more than 20.
When 1 to 12 are arbitrarily arranged, there are chances that numbers from 6 and above are having consecutive numbers.
These totals are greater than 20
Hence shown that some three consecutive players have the sum of their numbers at least 20.
(i.e. starting from if we take)
Answer:
m of angle s is 32
Step-by-step explanation: