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prisoha [69]
2 years ago
14

Which ordered pair is a solution to the inequality?

Mathematics
1 answer:
Over [174]2 years ago
7 0

Answer:

C.

Step-by-step explanation:

The equation would be -3 is less than 3(1)+1, which is 4. And -3 is less than 4.

(hope this helps!)

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Lapatulllka [165]
10 is 37.037 percent of 27
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I am an odd number.
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maybe itz

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Please help me!! I’m bad at math!!
tatyana61 [14]

Answer:

50.24

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And, you're not bad at math! You goot this correct! :)

Step-by-step explanation:

c=25.12

we can use this to find the raidus!

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plug it back into the circumference formula first.

c=(pi)(d)

25.12=3.14*d

divide both sides by 3.14!

d=8 but we need the radius, so we just divide by 2. 8/2 = 4. so the raidus is 4!

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now we plug it into the area of a circle formula.

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5 0
2 years ago
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Find the equation of the form y=ax²+bx+c whose graph passes through the points (1,6), (3, 20), and (−2,15).
Korolek [52]

Answer:

c = \dfrac{25}{4}

b = \dfrac{-13}{8}

a = \dfrac{11}{8}

Step-by-step explanation:

given ,

equation y=ax²+bx+c

passing through points (1,6), (3, 20), and (−2,15).

then these points will satisfy the equation

at (1,6)

y  = a x²+b x+c

6 = a(1)² + b (1) + c

a + b + c = 6------(1)

at (3 , 20)

y  = a x²+b x+c

20 = a(3)² + b (3) + c

9 a + 3 b + c = 20------(2)

at (−2,15)

y  = a x²+b x+c

15 = a(-2)² + b (-2) + c

4 a -2 b + c = 15------(3)

solving equation (1),(2) and (3)

a = 6 - b - c

9 (6 - b - c)+ 3 b + c = 20

6 b + 7 c = 34-------(4)

4 (6 - b - c) -2 b + c = 15

2 b + c = 3----------(5)

on solving equation (4) and (5)

c = \dfrac{25}{4}

b = \dfrac{-13}{8}

a = \dfrac{11}{8}

6 0
3 years ago
The probability of rolling two dice at the same time and getting a 4 with either die or the sum of the dice is 6
aleksklad [387]

Answer:

Suppose that the first die we roll comes up as a 1. The other die roll could be a 1, 2, 3, 4, 5, or 6. Now suppose that the first die is a 2. The other die roll again could be a 1, 2, 3, 4, 5, or 6. We have already found 12 potential outcomes, and have yet to exhaust all of the possibilities of the first die. But with a second dice, there will be 24 different possibilities.

Step-by-step explanation:

   1     2        3 4   5     6

1 (1, 1)   (1, 2)   (1, 3)   (1, 4)  (1, 5)   (1, 6)

2 (2, 1)   (2, 2)  (2, 3)  (2, 4) (2, 5)  (2, 6)

3 (3, 1)   (3, 2)  (3, 3)  (3, 4)  (3, 5)  (3, 6)

4 (4, 1)   (4, 2)  (4, 3)  (4, 4)  (4, 5)  (4, 6)

5 (5, 1)   (5, 2)  (5, 3)  (5, 4)  (5, 5)  (5, 6)

6 (6, 1)   (6, 2)  (6, 3)  (<u>6, 4</u>)  (6, 5)  (6, 6)

4 0
3 years ago
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