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3 years ago

What is the surface area of the rectangular prism shown below?

Mathematics

1 answer:

zmey [24]3 years ago

6 0

Answer: 238 ft ^ 2.

Step-by-step explanation:

To find surface area of a rectangular prism, use this formula:

$SA=2(l*w+w*h+h*l)$

To find the area of a normal rectangle, you would multiply the length by the width, so for the surface area of a rectangular prism, you're just finding the areas of the sides and adding them together.

Substituting 5 for h, 3 for w, and 13 for l, you can solve:

$SA = 2(13*3+3*5+5*13)\\SA = 2(39+15+65)\\\\SA = 2(119)\\\\SA = 238$

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Answer: Remember that the tens place is two moves to the left of the decimal point (if it exists). To round to the nearest ten (nearest 10), we use the whole numbers place to determine whether the tens place rounds up or stays the same.

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Step 1: Locate and underline the tens place () and look to digit to the right (6):

Step 2: In this case, the digit to the right 6 is 5 or above. So, we add 1 to the tens place (). The digit(s) after the (6) are dropped. Thus, we get 40 as answer.

In short: 36 rounded to the nearest tens is 40.

Step-by-step explanation:

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2 years ago

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3 years ago

Given that sec (x) = 2 and cosec (x) is negative,

weeeeeb [17]

Answer:

i) sin(2x) = $-\frac{\sqrt{3}}{2}$

ii) cot(x+360) = $-\frac{\sqrt{3}}{3}$

iii) sin(x-180) = $\frac{\sqrt{3}}{2}$

Step-by-step explanation:

sec(x) = 2

Since cos(x) is reciprocal of sec(x), this means:

cos(x) = $\frac{1}{2}$

cosec(x) is negative , this means sin(x) is also negative. The only quadrant where cos(x), sec(x) are positive and sin(x), cosec(x) are negative is the 4th quadrant. Hence the terminal arm of the angle x is in 4th quadrant.

Part i)

sin(2x) can be simplified as:

sin(2x) = 2 sin(x) cos(x)

First we need to find the value of sin(x). According to Pythagorean identity:

$sin^{2}(x)=1-cos^{2}(x)\\\\ sin(x)=\pm \sqrt{1-cos^{2}(x)}$

Since, angle is in 4th quadrant, sin(x) will be negative. So considering the negative value of sin(x) and substituting the value of cos(x), we get:

$sin(x)=- \sqrt{1-cos^{2}(x)}\\\\ sin(x)=-\sqrt{1-(\frac{1}{2})^{2}}\\\\ sin(x)=-\frac{\sqrt{3}}{2}$

So,

$sin(2x)=2 \times -\frac{\sqrt{3} }{2} \times \frac{1}{2}\\\\ sin(2x)=-\frac{\sqrt{3}}{2}$

Part ii)

We have to find cot(x + 360)

An addition of 360 degrees to the angle brings it back to the same terminal point. So the trigonometric ratios of the original angle and new angle after adding 360 or any multiple of 360 stay the same. i.e.

cot(x + 360) = cot(x)

$cot(x) = \frac{cos(x)}{sin(x)}\\$

Using the values, we get:

$cot(x)=\frac{\frac{1}{2}}{-\frac{\sqrt{3}}{2} }\\\\ cot(x)=-\frac{\sqrt{3}}{3}$

Part iii)

We need to find the value of sin(x - 180)

sin(x - 180) = - sin(x)

Addition or subtraction of 180 degrees changes the angle by 2 quadrants. The sign of sin(x) becomes opposite if the angle jumps by 2 quadrants. For example, sin(x) is positive in 1st quadrant and negative in 3rd quadrant.

So,

sin(x - 180) = $-(-\frac{\sqrt{3}}{2}) = \frac{\sqrt{3}}{2}$

6 0

3 years ago

What is the surface area of the rectangular prism shown below? ​

What is the surface area of the rectangular prism shown below?