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Alex_Xolod [135]
3 years ago
7

Which of the following is a polynomial?

Mathematics
2 answers:
lyudmila [28]3 years ago
7 0

Answer:

<em><u>D.</u></em>

Step-by-step explanation:

A polynomial is an expression that looks similar to this:

3x³+x-3

soldier1979 [14.2K]3 years ago
7 0

A POLYNOMIAL IN ONE VARIABLE is a polynomial that contains only one variable. Example: 5x 2 + 3x - 7.

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Find the measure of arc AB. Round to the nearest tenth if necessary.
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Your answer is 120 degrees.

Step-by-step explanation:

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Jeremy wants to give a 20% gratuity to his cab driver. His fare was $35.50. What is the total amount he will pay the driver?
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How can i determine the sale price if you were given the regular price and percent of markdown
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You would multiply the sales regular price by the percent and then subtract your answer from the regular sale price. For example, if something cost $499 and the sales price was 15% off, you would multiply 499 by 0.15 and then you would get 74.85.
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Simplify each expression. Assume that all variables are positive.
kozerog [31]
Q1. The answer is  \frac{8x^{3}y^{6}  }{27}

( \frac{16 x^{5} y^{10}}{81x y^{2} } )^{ \frac{3}{4} }= ( \frac{16}{81}* \frac{ x^{5} }{x}* \frac{ y^{10} }{y^{2}}   )^{ \frac{3}{4} } \\  \\ &#10;  \frac{ x^{a} }{ x^{b} }= x^{a-b}  \\  \\ &#10;( \frac{16}{81}* \frac{ x^{5} }{x}*\frac{ y^{10} }{y^{2}}   )^{ \frac{3}{4} }}=( \frac{16}{81 }* x^{5-1}* y^{10-2})^{ \frac{3}{4} }=( \frac{16}{81 }* x^{4}* y^{8})^{ \frac{3}{4} }= \\  \\ = (\frac{16}{18} )^{ \frac{3}{4} }*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=
\frac{(16)^{ \frac{3}{4} }}{(18)^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } \\  \\ &#10; (x^{a} )^{b} = x^{a*b}  \\  \\ &#10;\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } =  \frac{ 2^{4* \frac{3}{4} } }{ 3^{4* \frac{3}{4} } } * x^{4* \frac{3}{4} } * y^{8*\frac{3}{4}} = \frac{ 2^{3} }{ 3^{3} } * x^{3} *y^{6} = 
= \frac{8x^{3}y^{6}  }{27}

Q2. The answer is 1/16

(-64) ^ \frac{-2}{3} =(-1* 2^{6} ) ^ \frac{-2}{3}=(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} \\\\x^{-a} =  \frac{1}{ x^{a} } \\\\(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} = \frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{(2^{6})^ \frac{2}{3}} \\  \\  (x^{a} )^{b}=x^{a*b} \\\\x^{ \frac{a}{b} = \sqrt[b]{ x^{a} } }  \\  \\ &#10;
\frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{2^{6*\frac{2}{3}}} = \frac{1}{ \sqrt[3]{(-1)^{2} } } * \frac{1}{ 2^{4} } =  \frac{1}{ \sqrt[3]{1} } * \frac{1}{16} = \frac{1}{1} * \frac{1}{16}= \frac{1}{16}


Q3. The answer is a^{ \frac{7}{6} }

a^{ \frac{2}{3} } * a^{ \frac{1}{2} }  \\  \\ &#10; x^{a}* x^{b}  =x^{a+b}  \\  \\ &#10;a^{ \frac{2}{3} } * a^{ \frac{1}{2} }= a^{ \frac{2}{3} + \frac{1}{2} } =a^{ \frac{2*2}{3*2} + \frac{1*3}{2*3} }=a^{ \frac{4}{6} + \frac{3}{6} }=a^{ \frac{4+3}{6} }=a^{ \frac{7}{6} }
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Slope of j (0,0) , k (-2,8)
vichka [17]
I hope this helps you

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3 years ago
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