What is the answer to this question?

10$ is spent on 2 big pails and 1 small one. A smail pail cosf half as much as each big one. How much is spent on a big pail? Ho

Mila [183]

Answer:

$4 is spent on a big pail and $2 is spent on a small pail.

Step-by-step explanation:

Given:

10$ is spent on 2 big pails and 1 small one.

A small pail cost half as much as each big one.

Now, to find the amount spent on a big pail and on a small pail.

Let the cost of a big pail be $x.$

And the cost of small pail be $\frac{x}{2} .$

As given, there are 2 big pails.

And the total money spent = $10.

According to question:

$(x+x)+\frac{x}{2}=10$

$2x +\frac{x}{2}=10$

$\frac{4x+x}{2} =10$

$\frac{5x}{2} =10$

Multiplying both sides by 2 we get:

$5x=20$

Dividing both sides by 5 we get:

$x=4.$

The cost of a big pail = $4.

So, the cost of a small pail = $\frac{x}{2} =\frac{4}{2}=\$2.$

Therefore, $4 is spent on a big pail and $2 is spent on a small pail.

6 0

3 years ago

What is the measure of angle x? Enter your answer in the box.

Cloud [144]

Answer:

the measure of angle x is 48

7 0

3 years ago

Read 2 more answers

Crash Hospital Costs. A study was conducts to estimate hospital costs for accident victims who wore seat belts. Twenty randomly

kvv77 [185]

Answer:

a) The 99% confidence interval would be given by (5004.168;12603.832)

b) For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X =9004$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=5629 represent the sample standard deviation

n=20 represent the sample size

2) Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=20-1=19$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,19)".And we see that $t_{\alpha/2}=2.86$

Now we have everything in order to replace into formula (1):

$9004-2.86\frac{5629}{\sqrt{20}}=5004.168$

$9004+2.86\frac{5629}{\sqrt{20}}=12603.832$

So on this case the 99% confidence interval would be given by (5004.168;12603.832)

3) Part b

For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

7 0

2 years ago

Craig just purchased a new car. He financed $45000 and must pay it back over 5 years with 11% interest. a) How much will craig h

nignag [31]

Answer:

49950

Step-by-step explanation:

111% of 45000 is 49950

5 0

2 years ago

Read 2 more answers

John wants to invite around 78,000 college students to a tournament. Which of the following sets of college student populations