3 years ago

A circle has a radius of 6 in. The circumscribed equilateral triangle will have an area of:

2 answers:

8 0

The length of the side of an equilateral triangle that is circumscribed by a circle with radius r is s = r sqrt(3)so s = (6) sqrt(3)then the formula for the area of an equilateral triangle isA = sqrt(3) (s^2) / 4
substitute the value of s in the equationA = sqrt(3) ( (6) sqrt(3))^2 /4A = 46.77 sq in

Margaret [11]3 years ago

8 0

The answer is 108 $\sqrt{3}$

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3 years ago

Can someone help me with this?

Anna35 [415]

Answer:

Let 'a' be the first term, 'r' be the common ratio and 'n' be the number of terms

Series = 2+6+18.......= 2+2•3¹+ 2•3².......= 728

Now,

$Sum = \frac{a( {r}^{n} - 1) }{(r - 1)} \\$

So,

$\frac{a( {r}^{n} - 1)}{(r - 1)} = 728 \\ \frac{2( {3}^{n} - 1) }{(3 - 1)} = 728 \\ \frac{2( {3}^{n} - 1) }{2} = 728 \\ {3}^{n} - 1 = 728 \\ {3}^{n}=728+1\\ {3}^{n} = 729 \\ {3}^{n} = {3}^{6} \\ \boxed{ n = 6}$