Question

A circle has a radius of 6 in. The circumscribed equilateral triangle will have an area of:

Answer 1

The length of the side of an equilateral triangle that is circumscribed by a circle with radius r is s = r sqrt(3)so s = (6) sqrt(3)then the formula for the area of an equilateral triangle isA = sqrt(3) (s^2) / 4
substitute the value of s in the equationA = sqrt(3) ( (6) sqrt(3))^2  /4A = 46.77 sq in 

Answer 2

The answer is 108$\sqrt{3}$